1、null null 7 / I + I杨春花null( + 3 , i 400031)1 o M 文学翻译;创造性叛逆;译者K null 1 创造性叛逆分为创造性叛逆(或忠实的叛逆)和叛逆性创造(或叛逆的忠实)两大类,其创造性表明了译者以自己的艺术创造才能去接近和再现原作的一种主观努力,叛逆性反映了在翻译过程中译者为了到达某一主观愿望而造成的一种译作对原作的客观背离以及对译语的叛逆b创造性叛逆的主体是译者,不包括读者及其接受环境b m s | H059 D S M A c I | 1009- 9506(2006)02- 0045- 057 / I ! ? q B 5 ,T r #B c ( c
2、 ) 7 / I l a 8 a 5 b2004 M 11 , ? q $ + S B r “ V !,3 F V J r 7 / I r $ ! ) b 7/ I ! B Q , ? q r #B + Z b一a同一概念,不同内涵 J r , X J r ,Q 9 ! B 1 Z . J r 4 “ J. S J r , 2002, (6): 25- 28.Rethinkingon “CreativeTreason“YANG Chun- hua(Graduate School, Sichuan International Studies University, Chongqing 40003
3、1)KeyW ords: literature translation; creative treason; translatorAbstract:Creativetreason falls intotwo types: faithfultreasonand treasonous creation. Theircreativityshowsthe translators subjectiveefforttoapproachandreproducetheoriginalwithhisorherartisticcreativeability. Treanullson reflects theobj
4、ectivedeviationof translations from theoriginaldue to the translators efforts tomake a certainwishcome true. The subjectofcreative treason is the translator. The readerand the accepting context are irrelenullvan.t+ null + !谢德辉( 3 n , 2 653100)第一, 导!方法b E , E b = 1 = , 3 | Z E , : Q 1 : k , 1 , M B ,
5、 E B E , j M M M 1 E V E b q ! M q !b第二, 导!知识b = : M L a M a 4 Z , = s 1 i , 1 s , 4 1 M m l b P 3 g M 1 i P , 3 1 M 4 M , N M e b第三, 导!新质疑b , 3 , , 3 b 3 s 4 ,s P ,s 1 , , 7 X b 3 ? ? 4 , 4 , _ 3 C P 2 , r F y a a 8 ? C , 3 s (v s 3 s ), H 9 $ s ,7 ? , 3 ? “ 5 V C W s B ! ! , M M , z ! 3 ? b第四, 导!练
6、习b 3 M g f ? I bY V , 3 R p B 1 “ 8 ,s 3 p , Z E ; Y 3 i 5 Y V Y , : y 5 B n b “ ; V 3 g M , V ? C = 4 , = 9 , T b第五, 导!自学b 3 8 T ? $ 5 ? C , B M B 1 ? E b = 1 B ! 3 1 $ a1 , ! 3 W I I ? 8 , ! 3 as ? 8 , ! 3 ? C 5 a4 5 a I 5 % 5 ? 8 b 8 V , = = , _ 8 3 4 “ S 1 p , 3 1 , s s b第六, 导!组织b B 5 5 ,1 B = z
7、 M = , P , 1 F 5 z 3 , s B 3 8 i M by N 8 C : 1 H , 1 , r , !7 y , P 3 y r M b第七, 导!求索b Y V 3 1 - p , 3 a , 4 a t , P a , 7 ! 1 - s 5 a % 5 ? b 3 1 - p , % 3 m X V ,7 3 W a = 3 W . - = W H V , K v K 3 ,4 3 b 3 I , l F ) , , = 3 M k , 3 W M , Q Z P , = a H m , 3 = l b 3 1 - p , g z l ! b! 1 “ ,b 7 z - n , l J r M d B M , P 3 M “ a? S b9 , 3 Z 8 - 4 / , 3 9 8 b 3 Z 4 M V Z 4 ?p Q b 3 = ? 1 V T , ! l ? Z , “ il bnull49 = : 7 / I + I
