Unit 11.选词填空explore(v.勘探,探测 ) transmit(v.传送,传递,传播) resource(n.资源) emerge(v.出现,为所公认) yield(v.产生,出产,屈从,让步) pose(v.摆姿势,导致) assume(v.认为,假定,假设 ) confidence
微机原理第三版课后练习答案DOCTag内容描述:
1、Unit 11.选词填空explore(v.勘探,探测 ) transmit(v.传送,传递,传播) resource(n.资源) emerge(v.出现,为所公认) yield(v.产生,出产,屈从,让步) pose(v.摆姿势,导致) assume(v.认为,假定,假设 ) confidence(n.信任信赖,自信心) inherit(v.沿袭,秉承,继承) comprehensive(a.综合的,多方面的)1. Given the chance to show his ability, he regained confidence and began to succeed in school.2. It is so difficult to explore the bottom of the ocean because some parts are very deep.3. It was about 30 seconds befor。
2、Unit 1 The Way to SuccessSection A1 Understanding the text.1 He achieved fame for his wit, wisdom, civic duty, and abundant courage.2 They were thought to be slow learners in childhood, but they overcame their childhood difficulties and made magnificent discoveries that benefit the entire world today.3 His strong will.4 It means to keep their focus on achieving a positive end result, instead of letting small problems get in the way of good results.5 Because they have the will to overcome profoun。
3、第二章 8086 体系结构与 80x86CPU18086CPU 由哪两部分构成?它们的主要功能是什么?答:8086CPU 由两部分组成:指令执行部件(EU,Execution Unit)和总线接口部件(BIU,Bus Interface Unit)。指令执行部件(EU)主要由算术逻辑运算单元(ALU)、标志寄存器 FR、通用寄存器组和 EU 控制器等 4 个部件组成,其主要功能是执行指令。总线接口部件(BIU)主要由地址加法器、专用寄存器组、指令队列和总线控制电路等 4 个部件组成,其主要功能是形成访问存储器的物理地址、访问存储器并取指令暂存到指令队列中等待执行,访问存储器或 IO端口读取操作。
4、Unit 2 beat your fearSection APre-reading activities11T 2F 3T 4F SF21 Jacks problem is solved by a carpenter. He told Jack to cut the legs off the bed. And then Jack as certain that nobody was sleeping under it when he got into bed.2 The answer is open-ended. For example, you might have the fear of darkness, the fear of heights, the fear of snakes or spiders, the fear of flying, etc. Some suggestions on how to overcome fears are listed below for reference. First, you analyzed your fear an。
5、课后答案网 http:/www.khdaw.com课后答案网 http:/www.khdaw.com第二章P36-6(1)是 09组成的数字串LG()1(2)最左推导:NDNDDD010217345658最右推导: NNDND727127012743868568P36-7G(S)ONDSA1357924680|P36-8文法: ETFi|*/()最左推导: FTiiTFiiFiETETTiii*()()()()()()最右推导: FTiFiiiFiiTTEFii*()()()()()(语法树:/*课后答案网 http:/www.khdaw.com课后答案网 http:/www.khdaw.comEEFTE+TFFT+iiiEEFTE-TFFT-iiiEEFT+TFii*+i i- i+*/P36-9句子 iiiei有两个语法树:SieiSieiP36-10/*) (|ST*。
6、化工原理第三版陈敏恒课后答案课后学习网 www.khxxw.com 课后学习网解题思路:1. 已知:xf=15%,F=30kg ,S=60kg,单级萃取,在 25下,水(B)醋酸(A)乙醚(S)系统平衡数据如下表水层 乙醚层水 醋酸 乙醚 水 醋酸 0.933 0 0.067 0.023 0 0.88 0.051 0.069 0.036 0.038 0.84 0.088 0.072 0.050 0.073 0.782 0.138 0.080 0.072 0.125 0.721 0.184 0.095 0.104 0.181 0.65 0.231 0.119 0.151 0.236 0.557 0.279 0.164 0.236 0.287求:(1) E ,R,x,y (2) kA, 解题思路:乙醚 0.977 0.926 0.877 0.803 0.715 0.613 0.477(1) 由MSFF301=得图中 M。
7、Section AKey to ExercisesWords in use1.confidence 2. explore 3. emerged 4. assume 5. pose 6.comprehensive7.resources 8. yield 9. inherited 10. TransmitWord buildinguncover uneasy unload applicant resistant accountant assistsimplify notify qualify classify1. classified 2.assist 3. resistant 4. uncovered 5. uneasy 6. qualify7. unloading 8. applicants 9. simplified 10. accountant 11. NotifiedBanked cloze1. D 2. H 3. A 4.B 5. M 6.F 7. O 8. I 9. G 10.JExpre。
8、第二章P36-6(1)是 09组成的数字串LG()1(2)最左推导:NDNDDD010217345658最右推导: NNDND727127012743868568P36-7G(S)ONDSA1357924680|P36-8文法: ETFi|*/()最左推导: FTiiTFiiFiETETTiii*()()()()()()最右推导: FTiFiiiFiiTTEFii*()()()()()(语法树:/*EEFTE+TFFT+iiiEEFTE-TFFT-iiiEEFT+TFii*+i i- i+*/P36-9句子 iiiei有两个语法树:SieiSieiP36-10/*) (|ST*/P36-11/*L1: |cCabASL2: bcBaAS|L3:|aBbASL4: ABS|01|*/第三章习题参考答案P647。
9、结构设计原理答案(3-22 章)第 1 页3-16.截面尺寸 的钢筋混凝土矩形截面梁,采用 C25mhb502混凝土和 HRB335 级钢筋,I 类环境条件,安全等级为二级,最大弯矩组合设计值 ,试分别采用基本公式法和查表法进行截面设计(单筋截面)mkNMd145。解:基本公式法:查表可得: , , =1.0,f13.8Pacdf280MPasd0b.56(1)求受压区高度 x假设 ,则 ,60sam0564hm,0()2dcxfbh代入数据得: 61.04513.84x( )解之得:, 。70()xm去 0.56246.bxmhm(2)受拉钢筋面积 sA213.82130cdsfbx配 222 和 225, 实际配筋率27694s min01.0%0.23sAbh(3).截面复核。
10、.目录P36-61P36-71P36-81P36-92P36-102P36-112P647.3P648.4P6412.4P6414.6P811.7P812.8P813.11P1331.11P1332.11P1333.13P1345.14P1645.18P1647.18P2171.18.P2173.19P2184.19P2185.20P2186.21P2187.21P21912.21P2709.23P36-6(1)是 09组成的数字串LG()1(2)最左推导:NDNDDD010217345658最右推导: NNDND727127012743868568P36-7G(S)ONDSA1357924680|P36-8文法:.ETFi|*/()最左推导: FTiiTFiiFiETETTiii*()()()()()()最右推导: FTiFiiiFiiTTEFii*()()()()()(语法树:/*EEFTE+TFFT+iiiEEF。
11、新视野第三版 Book2 答案Keys to Unit 2 Text ALanguage focus: words in use31. promotes 2. accelerate 3. mystery 4. insight 5. boost6. analysis 7. calculate 8. barriers 9. destruction 10. prospect4Words learned New words formed-ing: promise promisingbear bearinghouse housing-iveobject objectiveoffensive offendexclusive excludeexcessive excessexecutive execute-yintense intensifyidentify 。
12、目录P36-61P36-71P36-81P36-92P36-102P36-112P647.3P648.4P6412.4P6414.6P811.7P812.8P813.11P1331.11P1332.11P1333.13P1345.14P1645.18P1647.18P2171.18P2173.19P2184.19P2185.20P2186.21P2187.21P21912.21P2709.23P36-6(1)是 09组成的数字串LG()1(2)最左推导:NDNDDD010217345658最右推导: NNDND727127012743868568P36-7G(S)ONDSA1357924680|P36-8文法:ETFi|*/()最左推导: FTiiTFiiFiETETTiii*()()()()()()最右推导: FTiFiiiFiiTTEFii*()()()()()(语法树:/*EEFTE+TFFT+iiiEEFTE-TFF。
13、1Unit 3 Social ProblemsIn-class Reading Passage课内阅读练习答案 Part One Preparation1. Describing the PicturesPicture A:A couple is dining at a restaurant. Both of them are smoking. But they call and complain to the waiter, saying that those sitting at the other tables are coughing too much and that bothers them. However, they have not realized that actually it is their smoking that has caused those people to cough. I have seen many people who behave like this couple. They never take other peop。
14、- 1 -第一章:绪论1 细胞生物学的任务是什么?它的范围都包括哪些? 1) 任务: 细胞生物学的任务是以细胞为着眼点,与其他学科的重要概念兼容并蓄,来阐明生物各级结构层次生命现象的本质。 2) 范围: (1) 细胞的细微结构; (2) 细胞分子水平上的结构; (3) 大分子结构变化与细胞生理活动的关系及分子解剖。 2. 细胞生物学在生命科学中所处的地位,以及它与其他学科的关系1)地位:以细胞作为生命活动的基本单位,探索生命活动规律,核心问题是将遗传与发育在细胞水平上的结合。2)关系:应用现代物理学与化学的技术成就和分子生物学的概。
15、编译 原理 课后题答案第二章P36-6(1)是 09组成的数字串LG()1(2)最左推导:NDNDDD010217345658最右推导: NNDND727127012743868568P36-7G(S)ONDSA1357924680|P36-8文法: ETFi|*/()最左推导: FTiiTFiiFiETETTiii*()()()()()()最右推导:ETFETiFiEiTiFiiEFii*()()()()*()(语法树:/*EEFTE+TFFT+iiiEEFTE-TFFT-iiiEEFT+TFii*+i i- i+*/P36-9句子 iiiei有两个语法树:SieiSieiP36-10/*) (|ST*/P36-11/*L1: |cCabASL2:bcBaAS|L3: |aBbASL4: ABS|01|*。
16、新视野第三版课后练习翻译吐泡泡工作室编制Book OneUnit One10.Translate the following paragraph into Chinese.Socrates was a classical Greek philosopher who is credited with laying the fundamentals (基础) of modern Western philosophy. He is a mysterious figure known chiefly through the accounts of later classical writers, especially the writings of his most famous student Plato, Socrates has become well known for his contribution to the field of ethics. His method of teaching, known as the Socratic 。
17、Unit 1 How to be a Successful Language LearnerText A Learning to Think All Over Again1 substituted 2 analogy 3 represented 4 associated 5 challenge 6 converted 7 concept 8 reduced 9 image 10 bundles 11 choose 12 pointed 13 instead 14 various 1 get away from 2 put together 3 getting into 4 broken into 5 a great deal 6 Over and over again 7 depend on1 took 2 go 3 take 4 go 5 go1 what caused the fire2 what site of shoe your father wears3 what looked like a ball4 what our family and friends do for u。
18、1 思考与练习题一、选择题1.计算机硬件中最核心的部件是( )。 CA.运算器 B.主存储器 C.CPU D.输入/输出设备2.微机的性能主要取决于( )。 A(B计算机数据处理能力的一个重要指标)A.CPU B.主存储器 C.硬盘 D.显示器3.计算机中带符号数的表示通常采用( )。 CA.原码 B.反码 C.补码 D.BCD 码4.采用补码表示的 8 位二进制数真值范围是( )。 CA.-127+127 B.-1 27+128 C.-128+127 D.-128+1285.大写字母“B”的 ASCII 码是( )。 BA.41H B.42H C.61H D.62H6.某数在计算机中用压缩 BCD 码表示为 10010011,其真值为( )。 CA.10010011B B.93H C.93 D.14。