1、 6RA70 e1 k 3“ !9 k M1 LA. kVb! !9 v A/B -_ z “d _ z L ,L_ z _I _ z w F H F E_ z _ J_ z _ z e_ z I |L_ z _“d = ! L9 1.6 “d !# z eb z PMU ? P051= 21 P051=22 H , PC 8 ! q ,O /4 8 , n m P052=0A U *t S ! b !z P075=0 V Kv $K- R072.01 z P078.01=575V L ,T #p z P078.02= 400V HL z T 4V j ,M1 n P351,P352,P361
2、-P364. z P076.02=70% H h !z P100(F)= - w (A) z P101(F)=- w (V) z P102(F)= - H (A) z P103(F)=Kl H (A),A l P102 50%. H ,B ! H . z P110(F)= w E ($ V1 ! z P111(F)= w (MH),V1 ! z P112(F)= H E ($),V1 ! z P118(F)=- EMF(V),EMF- =P101-P100*P110b z P119(F)=- (%) z P118,P119 Hh V P051=27 ! , P100,P101,P110? 3M
3、 , H9 “M , P118, L=- =P119* L=-EMF/P118. P102M H , Hh S . L= _ !z P083(F)= L= Q 4 z P083=3 ( wQ ) H 100% P115 H wQ z P083=2 ( I ) H 100% P143 z P140=0 1 I 1, Y 90 , / ,SI on - wQ P083=3 H 7 , I Q H P083=2 7o 1pb z P141=1024 I z P142=1 15V z P143(F)=I Q HK ( /s ) z P144(F)=I | 9 z P148(F)=1 P ?I S jr
4、 (F048#pr ) z P147=2 TI b1z f /9vN |9v. 9 B E L=_ ob H ? !z P081=0 HZ T z P081=1 HZ T z P082=2 r 07 ,V P258 H , 6 H P257. z P257(F)= 0 (%P102) T H z P615.02= 401 z P401= -3 3%*P078*1.35 ! H z ! v HYVQ ! w b K !z P642.01-04= 100 % ! K z P605.01-04=1 K z P171= 100%130%(P100 ) ,P172=-100-130%(P100 ) K
5、| f ? 3 M1 !z P303.01(F)= 10S z P304.01(F)= 10S z P305.01(F)=0.5S z P306.01(F)=0.5S z | F 1 ! ,? 0 K HW 10S,VHW 0.5S. ? !z P373(F)=1%( v 1% H 3 bit10 1) z P374(F)=0.5%( z ) z P375(F)=0.1S( HW ) z P771=107 ! 71 g 1 #p z P772=260 H_( 1#14#O z P773=261 HQ_( 1#14#O z 15#18#O P755=167P758= VP754=OFFSET !
6、 E 2T V U (0-+/- RPM) 1#14#O P755=117P758=7.5VP754=OFFSET ! E 2T w VV U (0-+A) z P820.04=0 |.#p P ? z P820.07=67 #p z P821.01=67 z P169=0, P170=1 K e H _ z R010 71 0-6 36-42 0 12 ESTOP| z R011 71 0V 46 0#p 7V 109/110 0C| z R015 L= wL V S = z R016 L= HL S = z R017 L=L q S = z R038 L= w 0b z R039 EMF
7、P101-P100*P110 _ Hz 71 HLM14 HVU f bz 1 z w H | He g = e /1.6 41 TJ 41 C 7 7 H 7 S V1 Hz Vv4b K| T - 1/ 1$ ! P110 P111 w E P112 H E P155 P156 w PI9m P255 P256 H PI9m P826:1 M HWn - ! P159=0.01,P160=0( 8 ) l P159P160 / SCR Q B V L_b -| 8b 1 w1J1F HWW4z wQ 1 f /S O11b| He g = e /1.6 41 TJ 41 C 7 7 H 7
8、 S Hz Vv4b- w F rKv -5 !1 L= ro | 1 8 roHW!1 s HW M61 9m I Q O AS yK vM 4 wQ Z TT L=1z : c kTB H z 1 z z 4S1 1 H Sbz : c kT I Z T Mz wQ Z T/ _I | _ L=AZ_Bz 11 4S _z I | f /T1SI Q Z T/H bz : c kT z 43 w3 &. L=A U HV wi: cz : c p (z 16 ( 1 1 wE H+z 71K 1 H : cTbz 714&. e/ Hh 114 K ebz _111 E IEB E= =
9、e !z P055=112P057=112| 1# F J 2# F4 = e4 R056R058 F4 f z P648.01(B)= 9, P648.02(B)= 3001 = e H e34 z P649.01(B)=9, P649.02(B)= 9 z P676.01(B)=P676.02(B)=17 71 0 39 T ? F FDS 4 , =e 4 1#F , e 4 2#F z P677.01(B)=677.02(B)=0. z P690.01 =17 71 0 39T ? F BDS4 , = e 4 1#F , e 4 2#F . z P644.01(F)=402 = eY
10、V P402 T , P644.02(F)=3002T e4 z P641.01(B)=0 P641.02(B)=17 71 0 39 T4| f ? 3 , = e 4 1#F , e 4 2#F . 7 P641.01=0 P641.02=1 z P580.02(B)=3500 e HQ_ K 1#14#O z P686.01(B)=P686.02(B)=24 BD y T#p$ E Y !z Y CBP l ,“ ADB PC1 q SIEM8045.GSD. z Y_| ! ,PLC“_ z P918=3 +D01 , 4 +D02 5 +D03 6 +D04 ,7(+D05), 8(
11、+D06), 9(+D07), 10(+D08), 11(+D09), 12(+D10), 13(+D11), 14(+D12), 15(+D13), 16(+D14), 17(+D15), 18(+D16), 19(+D17), 20(+D18)21 +D21YAC N z U710.01=U710.02=0 z U711=0 z U712=2 lY3 4PKW+6PZD z U722=0 #p F082 z P927=3 (CBP+PMU e ) E Y3 = !1-$.| 6A Uz Word 1-4 T PKW P ,il z Word 5 e3 P648.02=3001 (K3001
12、) z Word 6 P644.02=3002 (K3002) z Word7- Word8=0 z 114#O z Word09 0o 1p HQ_ e z 6. V PLC | P .1-$| 6 !z Word 1-4 T PKW P ,il z Word 5 3 1 z Word 6 -#p z Word 7 . Q z Word 8 . L= Q z Word 9 . L= Q z Word 10 . 3 3“Y !z P648.02=3001( e3 1 CBPB3 ) z P644.02=3002( 1 CBP=3 ) z P580.02=3500 HQ_ K 1#14#O z
13、U734.01=32 3 1 z U734.02=9811 -#p z U734.03=167. Q z U734.04=117. L= Q z U734.05=142. L= Q z U734.06= 20. 3 1-$IM1 | dz . PLC| WORD6. 3 K20 R010A U BIT1 37 0 o 1p CA1Hq BIT2 38 0 o 1p P ?A1Hq BIT3 39 0 o 1p = e BIT4 40 0 o 1p !z T 7 Hq V T #pb BIT5 41 0 o 0p C #p BIT6 42 0 o 0p SPD y #pb BIT7 43 0 o
14、 0p BD y T #p b BIT0BIT8-BIT15il BIT4-6T HMI #p . BIT0-BIT15 PLC %R 1-16 z PLC. WORD5. e3 ! (r650A U ) P648( e3 )=3001(L CBP sB3b K3001),/ 3001 e3 = W% . BIT0 e CsC ,. PLC | WORD6 . 3 K20 BIT3 ”0” H ,V X) e , O BIT2 ”1” HV 0 ”37”X , A1Hq ! f / V PLC esC , e . BIT1 OFF294 1 BIT2 OFF3 y T94 1 BIT3 P ?
15、 T e . . PLC| WORD6.3 K20 BIT3 ”0” H ,V X) e , O BIT3 ”1” HV 0 ”38”X , A1Hq ! f / VPLC e T . BIT4| ? 3 P ?94 1 BIT5| ? 3 94 1 BIT6 P ?94 1 BIT7 01 #p BIT894 0 BIT994 0 BIT104 e HA 1 BIT1194 1 BIT1294 1 BIT1394 0 BIT1494 0 BIT15#p| (1#p ), 94 1 z z . PLC| WORD5. 3 1(K32)r z BIT0= 1 !z z BIT1= 1 CQ z BIT2= 1 z BIT3= 1 #p z BIT7= 1 z BIT10= , | , L= , H ”0”. l
