1、(1)double fun(int n)(2)s=s+(double)a/b;(1)for(i=0;stri;i+)(2)if(substrk+1= 0)(1)t = *x ; *x = y ;(2)return(t) ;或 return t;(1)t=a;a=b;b=t;(2)return(b);或 return b;(1)*t=0;(2)if(d%2!=0)或 if(d%2=1)(1)去掉分号(2)case 1:case 2:return 1;(1)bk=*p;(2)bk= ;k+;(1)if( tti=a)(2)p=i;(1)#define FU(m,n) (m)/(n)(2)retur
2、n (value);(1)n=strlen( aa ) ;(2)ch=aai;(1)k+;(2)if(m=k)(1)void fun ( char *s , char *t )(2)t2*d=0;或 td+i=0;或 t2*d=0;或 td+i=0;(1)for(i=2;i=num)(2)t=s/n;(1)while(*s)或while（*s!=0）(2)s+;(1)sj+=si;(2)sj= 0;(1)double sum=0.0;(2)sum/=c;(1)while (*w)(2)if ( *r =*p )(1)t=calloc(m,sizeof(STU);(2)tk=bj;(1)doub
3、le r ;(2)while (fabs(n-m) 0.001)(1)int i, sl;(2)ti=ssl-i-1;(1)t=1.0;(2)return(s*2);(1)for(i=j+1;ip)(1)if(*r=*p) r+;p+; (2)if(*r=0)(1)IsPrime(int n) (2)if(!(n%i)if(k1)(1)int k, q, i;(2)pti = strki;(1)void fun(int *a,int *b)(2)t=*b; *b=*a; *a=t;(1)void fun(int *a, int n)(2)m=i;(1)void fun(char *str, c
4、har ch )(2)if ( *str != ch )(3)str1 = 0;(1)result*=n-;(2)return result;(1)if(*p= )(2)*(p-1)=toupper(*(p-1);(1)t+=1.0/i;(2)return t;(1)void fun(int *a)(2)aj=aj-1;(1)for(i=1;i=0(1)p=h-next;(2)p=p-next;(1)while ( i 0; i-)(2)if (tj tj+1)(1)void fun(int aM, int m)(2)ajk = (k+1)*(j+1);(1)for(i = 2 ; i= xa)(1)if(k%13=0)|(k%17=0)(2)(1)double fun(int k)(2)return s ;(1)double fun(int n)(2)return sum ;(1)char *fun( char *s,char *t)(2)ss+;(3)tt+;(1)p=s;(2)while(*p+);（1）int tN ,i, num=0; （2）tnum+=bi;或tnum=bi; num+; （3）for(i=0; i aij )
