1、=Q T5ps秦 振( 8) g, 277100)C 3=Q T5 HCp B ,s /,vE I.1. Q b1 a+ b 4b3a+ b =Q T,5aab( ) .(A) a= 0, b= 2 ( B) a= 1, b= 1( C) a= 0, b= 2a= 1, b= 1( D) a= 2, b= 0p:5i,a+ b= 2,4b= 3a+ b.a= 1,b= 1.#( B) .分析:py g =Q T Q.ya+ b 4b = 2 a+ bb, , b= 3a+b,7 4b = 3a + b. 6,YVa= 1,b= 19 p.:ya+ b 4b= 2 a+ bb,5i,a+ b=
2、2,b= 3a+ b.a= 0,b= 2.#(A) .2. Ia2= a( a 0) HiHq2 e( a- 1) - 1a- 1.p: ( a- 1) - 1a- 1= ( a- 1) 2# - 1a- 1= ( a- 1) 2# - 1a- 1= 1- a.分析:p Ia2= a H,i Hqa 0.5i- 1a- 1 0,a- 1 ba b H, T= a- ba- b = 1;( 2)a b) ,- 1( a b) .5. jVr Til5 k H, k2 - 3k+ 2 8ab2k2 - k- 22k2 - 7k+ 5 8ab3k2 - 5k+ 1 T?p:5i,k2- 3k+ 2=
3、 2k2 - 7k+ 5,2k2- k- 2= 3k2 - 5k+ 1. k2- 4k+ 3= 0.Z,k1 = 3, k2= 1.分析:k= 1 H, 2k2 - 7k+ 5= 0, k2-3k+ 2= 0,N H T 0, il.:p,k= 3 H, T.6./ 09 6 9 ( 2+ 1) A 13- 1 ( 3- 1) .p: ( 2+ 1) A 13- 1 ( 3- 1)= ( 2+ 1) A1= 2+ 1.分析:“ B) , ?,VPGQ .: ( 2+ 1) A 13- 1 ( 3- 1)= ( 2+ 1) ( 3- 1) ( 3- 1)= 4 2- 2 6- 2 3+ 4.7.
4、 V7 9 :m- nm+ n+n- pn+ p +p- mp + m.p: m- nm+ n+ n- pn+ p + p- mp + m= ( m- n) ( m- n)( m+ n) ( m- n) +( n- p ) ( n- p)( n+ p ) ( n- p) +( p- m) ( p- m)( p + m) ( p - m)= ( m- n)+ ( n- p)+ ( p - m)= 0.分析: ET , , Vi5.ym= nn= pp= m H, m - n = 0n - p = 0p - m= 0. s T,“5 .: m- nm+ n+ n- pn+ p + p- mp + m= ( m+ n) ( m- n)m+ n +( n+ p ) ( n- p)n+ p +( p + m) ( p - m)p+ m= ( m- n)+ ( n- p)+ ( p - m)= 0.292009 M1
