1、2012-10-22 6 1 2012 10 22 2012-10-22 6 2 181 5 7 9 11 10 292012-10-22 6 3 1 g A g K g A g K (1) g A ( 2 ) (2) g K ( 1 ) (3) g A g A ( 0 ) (4) g K g K ( 0 ) 2012-10-22 6 4 2 Y (t) Y(t) y (t) y (t) g K 0 y (t) y (t) = A (t) A(t) = g A (t) Y (t) Y(t) = K (t) K(t) = g K (t)2012-10-22 6 5 d y (t) y (t) d
2、t = g A (t) g A (t) y (t) y (t) A (t) A(t) t2012-10-22 6 6 d Y (t) Y(t) dt = g K (t) g K (t) Y (t) Y(t) K (t) K(t) t2012-10-22 6 7 t g K 0 Y (t) Y(t) = K (t) K(t) = g K (t) g K (t) y (t) y (t) = A (t) A(t) = g A (t) g A (t) 2012-10-22 6 8 g A (t) g A (t) g K (t) g K (t) Y (t) Y(t) y (t) y (t)2012-10
3、-22 6 9 1 1 + 1 + 1 (1- ) 1 g A = 0 g K = 0 3.8 g A g K A K L g A g K 2012-10-22 6 10 0 P139 3.8 + 1 g A g K g K = 0 n g A = 0 g A * g K * E - n 2012-10-22 6 11 g A g K E E g A g K 0 g A g K E ( g A * g K * ) 2012-10-22 6 12 g A * + n - g K * = 0 (3.16) g K * + n - ( -1) g A * = 0 (3.17) (3.16) g A
4、* + n = g K * (3.17) g A * + ( + )n +( -1) g A * = 0 (3.18)2012-10-22 6 13 g A * = ( + ) (1 - - ) n (3.19) g K * = ( 1 - + ) (1 - - ) n g K * g A * + n (3.1) A K g A * g K * g K * g A * 2012-10-22 6 14 E g A (t) = g K (t) = 0 g A * g K * 2012-10-22 6 15 g K = n + g A y (t) y (t) = A (t) A(t) = g A (
5、t) = Ba K K(t) a L L(t) A(t) -12012-10-22 6 16 a L a K g A a L a K g A g A g A * g A 0 g A t g A * 2012-10-22 6 17 g K = n + g A Y (t) Y(t) = K (t) K(t) = g K (t) g K (t) = 0 g K (t) K (t) K(t) = s (1- a K ) a (1- a L ) 1- a A(t)L(t) K(t) 1- a2012-10-22 6 18 s g K s g K g K g K * g K 0 g K t g K * 2
6、012-10-22 6 19 a L a K s 2012-10-22 6 20 g A * = ( + ) (1 - - ) n g K * = ( 1 - + ) (1 - - ) n g K * g A * n n g A * g K * g K * g A * 2012-10-22 6 21 1 0 0 2012-10-22 6 22 a L a K s a L 3.5 2012-10-22 6 23 2 2 + 1 g A = 0 g K = 0 3.9 A K 2012-10-22 6 24 0 P140 3.9 + 1 g A g K g K = 0 n g A = 0 - n
7、2012-10-22 6 25 Y (t) Y(t) = (1- a)g A + (1- a)n + a g K y (t) y (t) = Y (t) Y(t) - L(t) L(t) = (1- a)g A + (1- a)n + a g K n = (1- a)g A a n + a g K2012-10-22 6 26 g A g K g A g K 2012-10-22 6 27 g K (t) K (t) K(t) = s(1- a K ) a (1- a L ) 1- a A(t)L(t) K(t) 1- a s g K y (t) y (t) g K 0 g K y (t) y
8、 (t) 2012-10-22 6 28 g A = 0 g K = - n + (1- )g A (t) g K = 0 g K = n + g A (t)2012-10-22 6 29 n g K = n + g A g K = - n + (1- )g A (t) 2012-10-22 6 30 0 3.9 + 1 n g A g K g K = 0 n 1 g A = 0 - n n 22012-10-22 6 31 s n a L a K 1 2012-10-22 6 32 3 3 += 1 + = 1 (1- ) = 1 g A = 0 g K = 0 n g K = 0 g A
9、= 0 + 1 3.10 (a)2012-10-22 6 33 0 P141 3.10 + = 1 g A g K g K = 0 n g A = 0 - n 2012-10-22 6 34 2012-10-22 6 35 n = 0 (b) =1 n = 0 2012-10-22 6 36 0 P141 3.10 + = 1 , n = 0 g A g K g K = 0 g A = 02012-10-22 6 37 g A (t) = g K (t) = 0 g A g K y (t) y (t) = A (t) A(t) = g A (t) = Y (t) Y(t) = K (t) K(
10、t) = g K (t)2012-10-22 6 38 g A g K g A g K 2012-10-22 6 39 a L L 2 a L a K ( 3.6 )2012-10-22 6 40 g K (t) K (t) K(t) = s(1- a K ) a (1- a L ) 1- a A(t)L(t) K(t) 1- a s L g K = g A = y (t) y (t) = Y (t) Y(t) 2012-10-22 6 41 0 + = 1 , n = 0 s L g A g K g K = 0 g A = 02012-10-22 6 42 4 + = 1 , n = 0 (
11、 19902012-10-22 6 43 Romer, Paul (1990), “Endogenous Technological Change”, J. P. E. Vol. 98, No. 5, Part 2: The Problem of Development: A Conference of the Institute for the Study of Free Enterprise Systems. pp. S71-S102.2012-10-22 6 44 0 A (t)= B a L L A(t) (3.20)2012-10-22 6 45 Y(t) = K(t) a (1-
12、a L )L A(t) 1-a (3.21) K (t) = s Y(t) 2012-10-22 6 46 a L s a L s 2012-10-22 6 47 = 0 = 1 = 1 2012-10-22 6 48 (3.20) A Ba L L n = = 0 B a L L ( ) Ba L L 2012-10-22 6 49 ( ) 2012-10-22 6 50 2012-10-22 6 51 2012-10-22 6 52 2012-10-22 6 53 2.5 s a L a K 2 ( 7 ) s a L a K 2012-10-22 6 54 A” 2012-10-22 6 55 2012-10-22 6 56 2012-10-22 6 57 12012-10-22 6 58 2012-10-22 6 59 2012-10-22 6 60 ( ) 2012-10-22 6 61 2012-10-22 6 62
