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高一文科数学解析.doc

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1、高一文科数学解析一、选择题: 1-5 BCAAB 6-10 ADBCB二、填空题: 11、 (2,3) 12、 ;13、-7 14、 ; 15、 16、821n2323n;17、三、解答题:18解:() , ; 6 分401anS() 由 知 解得 ,9 分6513q25121q或当 时, ,此时2q43a当 时, ,此时 12 分1a2- 02-+=,2()45, 650251081021bxccabacxx x 22219.解 : 由 题 意 可 知 , 是 一 元 二 次 方 程 的 两 根 , 且 a 分 ( ) 分 分 不 等 式 -x即 为 分 分即 不 等 式 cx-b+a的 解

2、 集 为 | 分20 解:(1) 0cos)2(CbBa2 分22acc 02222 bcaba022acba4 分2cbca21os2B06 分3(2) 4,1cab223)(c16a10 分BcSABCsin23113 分421解:()设第 n 年获取利润为 y 万元n 年共收入租金 30n 万元,付出装修费构成一个以 1 为首项,2 为公差旳等差数列,共 -2 分2)1(因此利润 -4 分)8(30ny令 解得: 27所以从第 4 年开始获取纯利润-7 分()方案一:年平均利润 nnW8130)81(302(当且仅当 ,即 n=9 时取等号)12830所以 9 年后共获利润:12 =15

3、4(万元)-10 分469方案二:利润 14)5()81(3022nny所以 15 年后共获利润:144+ 10=154 (万元)-12 分两种方案获利一样多,而方案时间比较短,所以选择方案-14 分22解:() ;-3 分37,1,7432aa()由 知 , -6 分 )(1nn 21n所以数列 是以 5 为首项,2 为公比旳等比数列.所以 ,故 1253nna;-9 分3251na( )由( )知 ,采用分组求和法,可得bnn31-14 分()()2nnS一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一一

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