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大连理工大物2作业答案_40-44.pdf

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1、1I. 40TH1 S I T 86g ( S 5 iS 2 h:n UrIg I5H Zh:( UrI F/I: LI5H 40-1 -*cn : H U 1 1 O65 dcn :A /C (I: N UM e 0 IPp q 5A:_1 ETH:A.3 sa zT b :4cm2 T 640J BzT ) ( = 5:67 10 8W=m _K;b = 2:898 10 3m _K) 1fly y ; :M = T4E P = A T4dT = 4rPA =4s640J=60s4 10 4m2 5:67 10 8W=m K 828K4 -8 *5P 4:2eV = 200nm + g h

2、b B (1) P(2) O65 (3)I5P currency1 e = 1:6 10 19C;h = 6:626 10 34J s 1 P 0 = c 0= hcE = 6:626 1034 3 1084:2 1:6 10 19 m 2:96 107m = 296nm2 O65 Uc = h e U0 = hc U0 = 6:622 1034 3 108200 10 9 1:6 10 19 4:2 2V3 I5P currency1 12mv2m = eUc = 1:6 1019C 2V = 3:2 10 19J = 2eV5 ( S - v Ur , 10:6 m 00:4 m v; ,

3、 1 iM mT = b T2T1 =m1m21fly y M = T4 M2M1 = (T2T1 )4 = ( m1m2 )4 = (0:6 m0:4 m)4 = 5:06256 H/n H n H c I ; y T n H SX (5P c (c I- d e I e I eI y 1 c I c 2 n : c i( P p 27 (n c - 5P :0:6c (c -5P /vYb c -5P :Ek = E E0 = m0c2=p1 v2=c2 m0c2 EkE0 =1p1 v2=c2 1 =1p1 (0:6c)2=c2 1 = 0:258 ( c - g IIP 5P Yb I

4、 B (1)c IIP (2)5P currency1 1 c IP := 0 + (2h=m0c) sin2 (=2)E :m = 0 + 2h=m0cd c IIP hc= 0 = m0c2 0:511MeV Emin = hc m= hc 0 + 2hm0c= hc 0=(1 + 2(hc= )m0c) = m0c23 0:17MeV2 5P Emax = E0 + hc 0hc m= m0c2 +m0c2 m0c23 =53m0c2currency1 pm = 1cqE2max m20c4 = 43m0c 3:6 10 22kg m=s3II. 41TH1 “ P (:m curren

5、cy1 :Ek Q”H Bv W 1p = h c = h = hp = hp2mEk2 2 5PT-5P W :0:1nm B 5 1 5P /* d (” fEk = p22m =h22m 2 = eU U = h22m 2e =(6:626 10 34)22 9:11 10 31 10 20 1:6 10 19 151V3 41-1: _currency1:p 5P :a ( :R n gIO BO M 7-. a d. 1 W s = h=pU M a a :asin k = k 1 R d, sin 1 d=2R./d = 2Rsin 1 = 2R =a = 2Rh=pa4 0 =

6、hmec :5P n (me:5P Yb( h:n K8p c: z- I ) 5P currency1 I Yb B W . 1 5P currency1 I Yb d (” f 5P currency1p1d pp2c2 +m2ec4 mec2 = mec2p =p3mec 5P W := h=p = h=p3mec = 0=p35 - -Pcurrency1 :6:12 1012eV -P W -P Yb :mnc2 = 1:675 10 27 9 1016 9:42 108eV-P currency1p1d Ek =pp2c2 +m2nc4 mnc24dp = (1=c)pEk(Ek

7、+ 2mnc2)1 W s -P W := hp = hcpEk(Ek + 2mnc2)6:626 1034 3 108p6:12 1012 (6:12 1012 + 2 9:42 108) 1:6 10 19 2:03 10 19m 1 Ek m0c2 d p.5III. 42TH1 :2a P1- P p:(x) = 1pa cos 3 x2a ( a x a)1 B P(x = a2 2 ( a5 a)2 P Mn1dj (x)j2dx = 0 ssin(3 xa ) cos(3 xa ) = 0sin(3 xa ) = 0 / a)q2a sinn xa (0 x a)B 1 P (a

8、3 nn = 1/ 1m 20n = 1 m = 20n = 1 max = c 21= 1R(1=12 1=22) = 43R = 43 1:096776 107m 1 = 1:2157 10 7m = 121:57nmm =10n = 1 11 = c 11= 1R(1=12 12) = 1R = 0:9118 10 7m = 91:18nm2 ,3 “ P N I1 ; ,3 “ P N I1:n = 4!n = 3; 43 = c 43= 1R(1=32 1=42) = 1447R 1875:63nmn = 4!n = 2; 42 = c 42= 1R(1=22 1=42) = 163

9、R 486:27nmn = 4!n = 1; 41 = c 41= 1R(1=12 1=42) = 1615R 97:25nmn = 3!n = 2; 32 = c 32= 1R(1=22 1=32) = 365R 656:47nmn = 3!n = 1; 31 = c 31= 1R(1=12 1=32) = 98R 102:57nmn = 2!n = 1; 21 = c 21= 1R(1=12 1=22) = 43R 121:57nm1 I :390nm T P w : v n “ P l = 0;1;2;3 l 1ql* 5P n v 9 P-n = 2 -5P h p n;l;ml;ms

10、 / v n = 2 l = 0;1Sl = 1 ml = 0; 1Sl = 0 ml = 0ms = 12 n = 2 -5P h p:2;1;1;12; 2;1;1; 12; 2;1;0;12; 2;1;0; 122;1; 1;12; 2;1; 1; 12; 2;0;0;12; 2;0;0; 12E /8 v 9V. 44TH1 H/ H/ T L: P 0 N *IP IP / P$* K ( P PX( ee *IP cI N K P N d ee IP * ee IP M /currency1 I 7 IP 2 + P I y T I/ r IPw eIP h y s M /curr

11、ency1 G 3 H a Ppl Ppl a / H T Ppl Ih i( - Pp N Pp Ppl a Ppl P i( 3 4 CO2 Ih I :10:6 m.(1)B $* (2) w 7 sa CO2 S ):300K. B PpN1 PpN2K 2 /a ! I 3 If /T ( I Ur 6 I i( P : Nh: Ei Pp N1 N2 N4 N3 T 1 $* K Ppl 2 I 3 gI I1 * 1 3 4 K Ppl2 I = E4 E3h3 gI I1 6* 4!3;4!2;4!1;3!2;3!1;2!1:7 H/, J S , J S 5:6/ H T ,

12、 J S fl J SUvP UB( :w P u“% h , J S 5:6 , 0z AP 8 + S S J S : T S KClI PvSCl2;CO2I J S p J S n J S p J S ; 5P 0zE2K 86 IP +:= jE2 E1 jh ; = c = hcjE2 E1 jEE, J S 86 I max;o = hcEg= 6:626 1034 3 1081:2 1:6 10 19 m 10:35 107m 1035nmn J S 86 I max;n = hc E = 6:626 1034 3 1080:045 1:6 10 19 m 276:08 107m = 27608nm

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