1、 28 2006 3 J o u r n a lo f u z h o u T e a c h e r s C o lle g eVo l. 28 Ma r .2006 % 313000 ! . ! ! TM401 ! A ! 1009 17342006S0 0105 06 0 . 1 . . . . 1 c o s S 2 %c o s S 3 丛 P =P O +S 2 1R K1+C 2 2R K2 +C 2 3R K3.1 1 P O S1 R K1 = P K1 S 2 1NR K2 = P K2 S 2 2NR K3 = P K3 S 2 3N O kV 2. C2 +C3 =1.
2、2 C2 = S2 S1C3 = S3 S1 . 2 1 丛 P C2 丛 P =f C2. d丛 P d C2 =0 CJ2CJ2 = R K3 R K2 +R K3 .3% ! 2005 10 30 ! 19 77- . 9 CJ3 : CJ3 = R K2 R K2 +R K3 . ( 4 ) 9 9 . 9 . 丛 P J : 丛 P J =P O +S 2 1 R K1A + P 2 K3R K2 +P 2 K2R K3 ( P K2 +P K3 ) ( ) 2 . 2 1 : 1 A B 9 c o s S 2A %c o s S 3A %c o s S 2B%c o s S 3B
3、 9 : C2A = S2A S2A +S3A = S2A S1A ; C3A = S3A S2A +S3A = S3A S1A 9 C2B= S2B S2B+S3B = S2B S1B ; C3B= S3B S2B+S3B = S3B S1B 9 C2A +C3A =1 ; C2B+C3B=1. : D1A.= S1A S1A +S1B = S1A S1G ; D1B.= S1B S1B+S1B = S1B S1G . D1A.+D1B.=1 ; S1G =S1A +S1B. A B 9 丛 P A. B : 丛 P A. B=P OA +P OB+S 2 18 D 2 1A ( R K1A
4、 +C 2 2AR K2A +C 2 3AR K3A ) +D 2 1B. ( R K1B+C 2 2BR K2B+C 2 3BR K3B ) . ( 5 ) 9R K1A R K2A R K3A R K1B KK2BR K3B A B . : R K1A.= P K1A S 2 1NA ; R K1B= P K1B S 2 1NB ; R K2A = P K2A S 2 2NA ; R K2B= P K2B S 2 2NB ; R K3A = P K3A S 2 3NA ; R K3B= P K3B S 2 3NB . 6 0 1 28 P K1AP K2AP K3AP K1BP K2BP
5、K3B AB . 5 D1AD1B C2AC3AC2BC3B . 5 S1G 丛 P A B D1A 丛 P A B=f D1A 5 d丛 P A B dD1A =0 AB DJ1A = R K1B+C 2 2BR K2B+C 2 3BR K3B R K1A +C 2 2AR K2A +C 2 3AR K3A +R K1B+C 2 2BR K2B+C 2 3BR K3BDJ1B= R K1A +C 2 2AR K2A +C 2 3AR K3A R K1A +C 2 2AR K2A +C 2 3AR K3A +R K1B+C 2 2BR K2B+C 2 3BR K3B6DJIA DJIB = R
6、 K1B+C 2 2BR K2B+C 2 3BR K3B R K1A +C 2 2AR K2A +C 2 3AR K3A .6 AB 丛 P JA . B. 3 4 AB CJ2ACJ2BCJ3ACJ3B CJ2A = P K3A P K2A +P K3ACJ3A = P K2A P K2A +P K3ACJ2B= P K3A P K2B+P K3BCJ3B= P K2B P K2B+P K3B . AB 丛 P JA B 丛 P JA . B=P OA +P OB+S 2 18 D 2 JIA R K1A + P 2 K3AR K2A +P 2 K2AR K3AP K2A +P K3A2 +
7、D 2 J1B R K1B+ P 2 K3BR K2B+P 2 K2BR K3BP K2B+P K3BL J 2 . 3 ! 2 I * 2A =I 2GZ12B+I 3BZ1B-13AZ1AZ 12A +Z 12B7I * 2B=I 2GZ12A +I 3AZ1A -13BZ1BZ 12A +Z 12B.8 7 8 S * 2A = S2GUK12B% UK12A% +UK12B% + S3BUK1B% -S3AUK1A% UK12A% +UK12B% . S * 2B= S2GUK12A% UK12A% +UK12B% - S3BUK1B% -S3AUK1A% UK12A% +UK12B%
8、 . UK12A%UK13A%UK23A%UK12B%UK13B%UK23B% AB UK1A%UK2A%UK3A%UK3A%UK1B%UK2B%UK3B% AB . C2G = S2G S1G C3G = S3G S1G D3A = S3A S3A +S3B = S3A S3G D3B= S3B S3A +S3B = S3B S3G 7 0 1 2006 C2G +C3G =1 ; D3A +D3B=1. ( 9 ) T B= UK1B% UK12A% +UK12B% ; T A = UK1A% UK12A% +UK12B% ; G B= UK12B% UK12A% +UK12B% ; G
9、A = UK12A% UK12A% +UK12B% ; G B+G A =1 ; 8 = C3GD3BUK1B% -C3GD3AUK1A% UK12A% +UK12B% =C3GD3BT B-C3GD3AT A ; S * 2A = ( G BC2G +8 ) S1G S * 2B= ( G AC2G -8 ) S1G . ( 10 ) . 8 . 8 =0 S * 2A S * 2B = G B G A = UK12B% UK12A% . A B 丛 P * AB : 丛 P * AB =P OA +P OB+S 2 1G C 2 3G ( D 2 3AR K3A +D 2 3BR K3B
10、) + ( G BC2G +8 ) 2 R K2A + ( G BC2G +8 +C3GD3A ) 2 R K1A + ( G AC2G -8 ) 2 R K2B+ ( G AC2G -8 +C3GD3B ) 2 R K1B . . 丛 P * AB D3A 丛 P * AB =f ( D3A ) DJ3A 丛 P * AB 丛 P * JAB d丛 P * AB dD3A =0 DJ3A : DJ3A = C3G ( R K3B+T BR K2A +T BR K2B ) +C2G ( G BR K2A -G AR K2B ) C3G ( R K3A +R K3B+R K2A +R K2B )
11、 . ( 11 ) UK1% UK2%UK3% UK2% UK2% %0 UK1% % UK12%UK3% %UK23% . ( 10 ) : S * 2A =S1G/ 2 -S3A. S * 2B=S1G/ 2 -S3B. . 4 3 : S3A = S2G ( B U1B% -G U12B% ) +S3G ( B U13B% -G U1B% ) B Y -G 2 ; S3B= S2G ( B U1A% -G U12A% ) +S3G ( B U13A% -G U1A% ) B Y -G 2 . ( 12 ) S2A = S2G ( Y U12B% -G UK1B% ) -S3G ( Y U
12、K1A% -G UK13A% ) B Y -G 2 ; S2B= S2G ( Y U12A% -G U1A% ) -S3G ( Y U1B%G -U1K13B% ) B Y -G 2 . ( 13 ) G =UK1A% +UK1B% ; B =UK12A% +UK12B% ;Y =UK13A% +UK13B% . 8 0 1 28 . 9 . 5 5. 1 9 D2A D2B : D2A = S * 2A S2G = G BC2G +8 C2G ; D2B= S * 2B S2G = G AC2G -8 C2G . D2A D2B : D2A = C2A D1A C2G ; D2B = C2B
13、D1B. C2G . ( 14 ) DJ2A DJ2B : DJ2A = C2ADJ1A C2ADJ1A +C2BDJ1B ; DJ2B= C2BDJ1B C2ADJ1A +C2BDJ1B . 丛 P A B D1A. 9 ( 13 ) 丛 P A B 丛 2A. . 9 : DJ2A -D2A DJ2A -D2A 9 . 5. 2 9 A D3A : D3A = S2G ( B U1B% -G U12B% ) +S3G ( B U13B% -G U1B% ) S2G B ( U1B% +U1A% ) -G ( U12B% +U12A% ) +S3G B ( U13B% +U13A% ) -G
14、 ( U1B% +U1A % ) . ( 9 ) 9A D3A 9 ( 11 ) A DJ3A 9 : DJ3A -D3A. DJ3A - D3A 9 . 6 110kV . 110kV 1 . . 9 ( 288 ) 9 . 110kV 2 9 9 0. 9 5. 2 35kV 9 . 1 110kV 1 2 SN ( MVA ) 31. 5 31. 5 P 0 ( KW ) 47. 1 34 P K12 ( KW ) 169. 47 19 7. 53 P K13 ( KW ) 183 . 73 174 . 78 P K23 ( KW ) 135. 73 120. 42 UK12 % 10.
15、 25 10. 6 UK13 % 18 . 35 18 . 3 UK23 % 6. 58 6. 8 9 0 1 2006 : 2 110kV 1 2 35kV MVA-2. 9 9 6. 72 10kV MVA16. 16 5. 35 10 S * 2A =-3. 80MVAS * 2B=7. 53MVA. D2A = -3. 80 3. 73 =-1. 02D2A = -2. 9 9 3. 73 =-0. 80DJ2A =-0. 40. DJ2A -D2A DJ3A -D3A . 丛 P =143. 5KW丛 P*=145. 0KW丛 PI=133. 6KW. . 7 1 3 2 . . 3
16、 .2 UK1% %UK12%UK3% %UK23% .3 . !1 . M. 19 9 9.2 . J. 2004150 51.3 . J. 2004423 28 .4 . J. 200121449 52. 0 1 1 28 三绕组变压器运行方式损耗计算及经济性分析 作者： 夏远福 作者单位： 湖州电力局,浙江,湖州,313000 刊名： 湖州师范学院学报 英文刊名： JOURNAL OF HUZHOU TEACHERS COLLEGE 年，卷(期)： 2006,28(z1)参考文献(4条) 1.胡景生 变压器经济运行 1999 2.郑国华 三绕组变压器并联运行经济分析期刊论文-能源与环境
17、2004(01) 3.胡景生 电网经济运行节电技术综述期刊论文-节能 2004(04) 4.余永平 三绕组自偶变压器与普通变压器并列运行的研究与实施期刊论文-电力自动化设备 2001(04)本文读者也读过(10条) 1. 谷广亮 浅谈变压器几种运行状态的分析期刊论文-大众科技2008(8) 2. 张春华 谈谈变压器的并联运行设计期刊论文-江西建材2005(2) 3. 陆地.LU Di 输电系统中变压器的最佳运行分析期刊论文-高压电器2007,43(4) 4. 陈勇.韩军 变压器的经济运行方式会议论文-2007 5. 周东社.朱萍 并联变压器经济运行的简易判定方法期刊论文-节能与环保2008(8) 6. 张国军 变压器的经济运行与经济效益分析期刊论文-露天采矿技术2004(3) 7. 裴丹军 浅议变压器并列运行的条件期刊论文-中国西部科技2008,7(4) 8. 王俊.Wang Jun 三绕组变压器的经济运行分析期刊论文-广东输电与变电技术2007(4) 9. 周子参 合理投切降低变压器电能损耗期刊论文-科技信息(科学教研)2007(35) 10. 王泽宽 不停电倒换电源时的变压器并联问题探讨期刊论文-甘肃科技2005,21(1)本文链接：http:/
