收藏 分享(赏)

空调原理2.ppt

上传人:hskm5268 文档编号:8832721 上传时间:2019-07-13 格式:PPT 页数:102 大小:1.66MB
下载 相关 举报
空调原理2.ppt_第1页
第1页 / 共102页
空调原理2.ppt_第2页
第2页 / 共102页
空调原理2.ppt_第3页
第3页 / 共102页
空调原理2.ppt_第4页
第4页 / 共102页
空调原理2.ppt_第5页
第5页 / 共102页
点击查看更多>>
资源描述

1、温湿度处理过程,第二部分,约克中国培训中心,课程安排,标准工况 显热与潜热处理过程 显热因子 休息 图解过程 加热加湿 制冷去湿 通风 再热,空气处理装置中的热传递过程,出风 15.6 C,新风 32 C,回风 24 C,混合空气 26.7C,冷冻水出水 5.6C,过滤器,制冷盘管,冷冻水回水 12.8 C,Dry-bulb temperature,Specific Humidity (lbs. moisture/ lb. dry air),标准工况,标准工况 70F 14.7 psia (大气压力) 含湿量为0(没有水蒸汽) 标准工况下比容 = 13.35 cu. ft. / lb,标准工况

2、,公式,QSH F = SCFM x T x 1.08 QLH F = SCFM x gr x 0.68 QTOT = SCFM x h x 4.5 QTOT = QSH + QLH QX is in Btuh,显热,显热,显热,显热,冷却,显热,冷却,加热,显热,冷却,加热,显热变化,显热,显热变化示例,5000 CFM 从 80F DB/ 0 grains 加热到 90 F DB / 0 grains,5000 CFM 从 80F DB/ 0 grains 加热到 90 F DB / 0 grains,显热变化示例,5000 CFM 从 80F DB/ 0 grains 加热到 90 F

3、DB / 0 grains,显热变化示例,SCFM =,actual CFM actual sp vol,X 13.35 cu. ft. / lb,5000 CFM 从 80F DB/ 0 grains 加热到 90 F DB / 0 grains,显热变化示例,SCFM =,actual CFM actual sp vol,X 13.35 cu. ft. / lb,SCFM =,5000 13.6,X 13.35 cu. ft. / lb,5000 CFM 从 80F DB/ 0 grains 加热到 90 F DB / 0 grains,显热变化示例,SCFM =,actual CFM a

4、ctual sp vol,X 13.35 cu. ft. / lb,SCFM = 4908 SCFM QSHF = SCFM x T x 1.08 QSHF = 4908 x (90F- 80F) x 1.08 QSH = 53,006 Btu/h,SCFM =,5000 13.6,X 13.35 cu. ft. / lb,5000 CFM 从 80F DB/ 0 grains 加热到 90 F DB / 0 grains,显热变化示例,潜热,潜热,潜热,潜热,去湿,潜热,去湿,加湿,潜热,潜热变化,去湿,加湿,潜热,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿

5、量增加到 20 grains,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿量增加到 20 grains,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿量增加到 20 grains,SCFM =,actual CFM actual sp vol,X 13.35 cu. ft. / lb,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿量增加到 20 grains,SCFM =,actual CFM actual sp vol,X 13.35 cu. ft. / lb,SCFM =,6339 13.84,X

6、13.35 cu. ft. / lb,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿量增加到 20 grains,SCFM =,actual CFM actual sp vol,X 13.35 cu. ft. / lb,SCFM = 6115 SCFM QLHF = SCFM x gr x 0.68 QLHF = 6115 x (20 - 0) x 0.68 QLH = 83,164 Btu/h,SCFM =,6339 13.84,X 13.35 cu. ft. / lb,潜热变化示例,6339 CFM 从 90F DB/ 0 grains 使含湿量增加到 20

7、grains,Total Heat,全热量,全热量 h,全热量,全热示例,6000 CFM 从 60F DB/ 0 grains 加热加湿到 90F DB/ 20 grains 试问焓值变化量?,全热示例,6000 CFM 从 60F DB/ 0 grains 加热加湿到 90F DB/ 20 grains,全热示例,6000 CFM 从 60F DB/ 0 grains 加热加湿到 90F DB/ 20 grains,24.9,14.4,全热示例,6000 CFM 从 60F DB/ 0 grains 加热加湿到 90F DB/ 20 grains,SCFM = 6119 SCFM QTOT

8、F = SCFM x h x 4.5 QTOTF = 6119 x (24.9 - 14.4) x 4.5 QTOT = 289,123 Btu/h,SCFM =,6000 13.09,X 13.35 cu. ft. / lb,24.9,14.4,全热示例,6000 CFM 从 60F DB/ 0 grains 加热加湿到 90F DB/ 20 grains,回风与供风,RA,回风与供风,RA,SA,回风与供风,过程线,RA,SA,回风与供风,RA,SA,回风与供风,加热加湿,RA,SA,室内过程,回风与供风,加热加湿,加热加湿,RA,SA,机组内过程,室内过程,回风与供风,室内空气与供风,去

9、热去湿,SA,RA,室内过程,机组内过程,显热因子 (SHF),显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,显热因子 (SHF),78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,50,000 50,000 + 10,000,显热因子 (

10、SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btuh 潜热损失 = 10,000 Btuh,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,50,000 50,000 + 10,000,SHF =,0.833,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,SHF,.833,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,50,000 50,000 + 10,000,SHF =,0

11、.833,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,SHF,.833,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,50,000 50,000 + 10,000,SHF =,0.833,显热因子 (SHF),基准工况:78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,SHF,50% RH,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,78,显热因子 (SHF),基准

12、工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,SHF,50% RH,78,SHF =,QSH QSH + QLH,=,QSH QTOT,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,50% RH,78,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,显热因子 (SHF),基准工况:

13、 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,SHF =,0.889,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,.889,78,50

14、% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,SHF =,0.889,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,.889,78,50% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,SHF =,0.889,显热因子 (SHF),基准工况: 78F / 5

15、0% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,.889,78,50% RH,40% RH,75,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,SHF =,0.889,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,SHF,.88

16、9,78,50% RH,40% RH,75,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,40,000 40,000 + 15,000,SHF =,0.889,显热因子 (SHF),基准工况: 78F / 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,75F/ 40% RH 40,000 Btu/h 15,000 BTU/H,休息,图解过程,加热加湿 制冷去湿 通风 再热,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,加热加湿,78,120,加热

17、加湿,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,Hot Water Coil,Humidifier,Fan,Room,78,120,加热加湿,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,A,Fan,Room,A,78,120,Hot Water Coil,加热加湿,Humidifier,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,A,B,Fan,Room,A,B,78

18、,120,Hot Water Coil,加热加湿,Humidifier,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,A,B,C,Fan,Room,A,B,C,78,120,Hot Water Coil,加热加湿,Humidifier,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,A,B,C,Fan,Room,A,B,C,78,120,Hot Water Coil,加热加湿,Humidifier,室内设计工况: 78F/ 50% RH 显热损失 =

19、 50,000 Btu/h 潜热损失 = 10,000 Btu/h,Fan,Room,A,B,C,78,120,Hot Water Coil,RA,SA1,SA,加热加湿,Humidifier,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,78,120,RA,SA1,SA,加热加湿,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,78,120,RA,SA1,SA,加热加湿,需要多大风量(SCFM)?,室内设计工况: 78F/ 50% RH 显热损失

20、= 50,000 Btu/h 潜热损失 = 10,000 Btu/h,78,120,QSHF = SCFM x T x 1.08,RA,SA1,SA,加热加湿,需要多大风量(SCFM)?,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,QSH T x 1.08,78,120,SCFM,=,RA,SA1,SA,加热加湿,QSHF = SCFM x T x 1.08,需要多大风量(SCFM)?,室内设计工况: 78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,50,000

21、Btu/h (120F- 78F)x1.08,QSH T x 1.08,78,120,SCFM,=,SCFM,=,RA,SA1,SA,加热加湿,QSHF = SCFM x T x 1.08,需要多大风量(SCFM)?,室内设计工况:78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,QSH T x 1.08,78,120,SCFM,=,SCFM,=,SCFM,=,1102 SCFM,RA,SA1,SA,加热加湿,QSHF = SCFM x T x 1.08,50,000 Btu/h (120F- 78F) x 1.08,需要多大风量(SCFM

22、)?,室内设计工况:78F/ 50% RH 显热损失 = 50,000 Btu/h 潜热损失 = 10,000 Btu/h,制冷去湿,SHF,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,SHF,制冷去湿,75,SHF,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,75,SHF,SHF =,QSH QSH + QLH,=,QSH QTOT,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h

23、潜热损失 = 20,000 Btu/h,75,SHF,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,75,SHF,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,75,S

24、HF,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,75,SHF,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,75,SHF

25、,90% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20

26、,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,SHF =,QSH QSH + QLH,=,QSH QTOT,SHF =,80,000 80,000 + 20,000,SHF =,0.800,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,Fan,Room,Cooling Coil,RA,SA,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h

27、,54.5,75,SHF,90% RH,SA,RA,.800,制冷去湿,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,制冷去湿,需要多大风量(SCFM)?,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,QSHF = SCFM x T x 1.08,制冷去湿,需要多大风量(SCFM)?,室内设计工况: 75F/ 64 gr. 显热损

28、失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,QSH T x 1.08,QSHF = SCFM x T x 1.08,SCFM,=,制冷去湿,需要多大风量(SCFM)?,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,80,000 Btu/h (75F- 54.5F) x1.08,QSH T x 1.08,QSHF = SCFM x T x 1.08,SCFM,=,SCFM,=

29、,制冷去湿,需要多大风量(SCFM)?,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,54.5,75,SHF,90% RH,SA,RA,.800,QSH T x 1.08,需要多大风量(SCFM)?,QSHF = SCFM x T x 1.08,SCFM,=,SCFM,=,3613 SCFM,制冷去湿,80,000 Btu/h (75F- 54.5F) x 1.08,SCFM,=,室内设计工况: 75F/ 64 gr. 显热损失 = 80,000 Btu/h 潜热损失 = 20,000 Btu/h,练习,练习四:表面温度为50F的水管流过一干球温度 为75F,在管路上没有出现凝露现象,试问房间相对湿度的最大可能值为多少? 练习五:95F db / 75F wb 空气被冷却去湿至80F db / 50% rh,试求焓值变化? 练习六:30F db / 80% rh 空气通过一加热盘管加热至75F db,试确定加热后空气露点温度、湿球温度和相对湿度。 练习七:1000cfm空气由80F db / 50% rh冷却去湿至50F db / 100% rh,试求显热及潜热量变化。,参考答案,

展开阅读全文
相关资源
猜你喜欢
相关搜索
资源标签

当前位置:首页 > 企业管理 > 管理学资料

本站链接:文库   一言   我酷   合作


客服QQ:2549714901微博号:道客多多官方知乎号:道客多多

经营许可证编号: 粤ICP备2021046453号世界地图

道客多多©版权所有2020-2025营业执照举报