1、第二章选频网络注意：有部分答案有差异；3-1题是2-1题；只有计算题答案和部分问答题；答案不齐全。( pF).(LCH)(.QR L RffQ( k Hz )fMHz : f.15910159101432 11159101432 10100101001010 10121010990101211362620603670036700= =, .CL CL) (, .CL CL) (, .CL CL) : (220 2110 1220 2110 1220 2110 111311211123=RR CLR)LCL(j R)LCLR(j CLRCj RLj R)Cj L) ( Rj ( R: Z =+=
2、+=+= 2112111133220020020000) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )31801040450105351432 1121535100160512405354501605151431 223202222H.CCLpF- CCC pF CCC :=+=+=+=+=+=+。L C C( ) ( )( )( )mVVQVVmA.RVIHCLRC : Q-S mCo mLo m-o mo m-2121012122051011121010010511432 1121251010010511432 11533031 22602001 26000=( )
3、 ( )( ) ( )( )( )jj.CjRZ.QLQLRpFCpF.LCC CC.VVQH.C : LXXXXXXXSC79674710200101432 17471747100 102531014321052 1025310143220010010253101432 11100101025310100101432 11631 26066660006262001 22620=+=( ) ( )( ).21k0.5R,R, 0.5QQ, f22f 232010510555231002310010150105222010501051432 1173000 . 70 . 766003670001
4、 2620电阻所以应并上= = .ffQffQHC : L.= gQCffCfCf :. 0700070 22483( ) ( ) ( )( )( ) ( )( )( )MHz.Qff.LRQk RC CCCRRRk CLQRMHzLCfpF.CCC CCCC : CL.LPiPi481228 1064122281080106411432 10885885520 20202092010920102020 10801006411031810801432 12 1318202020 2020205936070663020211021 261 201 260102102= = += +=+ =+=+
5、=) RZ30Z20Z1123f1f1f1=解：) ( )( ) ( )( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ).j.jZMZjjCLjRZpF.LCk Hz.R fQff.RRLQk CRR LZRMZH RMpF.LCCH.LL :f.fffP843768010020 101831014321002010177101432 11015910143220117710159109501432 11522810 201022224252020 10159101432325101592020 101592020 1018310143
6、22183101432 20115910159101432 11159101432 1011332662 220 111 266620 210 222 2623220 2236110070661110 111 261111266220 1160 11626120 121630 1121=+ =+= += +=+ =+=+ =+= =( )1001014102220020101591050 10159153367.00111 236= = ffQMRRCR LRfP解：) ( ) ( ) ( )( )( ) ( ) ( )013.02001122211222005 101001032510102
7、40205 1010010205101011632207.06710 16710 12671120 1267220 11=+=+=+ =+=QffRLQRMkRR LRRMR :fa bf5.75.22303021103001010112118.111020001030014.325.22 115.2225.1 1103001010112111732332001 230233200= += += += +=QQQQf fQIICQRQQf fQII :( ) =+= L HL CLLCL: 12537511218321212第三章高频小信号放大器5102501050501501,5012.11
8、02501020501501,20491025010501501,154266200266200266200= +=+= +=+= +=+=TTTffMHzfffMHzfffMHzf当当解：当( ) ( ) ( )( )( )( ) ( ) ( ) ( )( )( ) ( ) ( )( )( ) ( ) ( )( ) ( )( )mSj.j.jbaj bagrCjbaj baCjggrCjgymSj. jba j bagymSj. j.jba j baCjgymS.j.j.jbaj baCjgyrCb.grapF. .fgCmSrgmS.Igmbbcbcbcbmbbcbc eo emf ecb
9、cbr eebebi ebbebebbbTmebebmEeb68.0049.0101 1.01107.377011031014321733.3327.37101 1.01107.37187.00187.0101 1.0110310143241189501011.01102410143210754.0107010241014321107540701124102501432 10737273710754050754015026 1126742231 27222222322221 2722221 273221 27363300+= + + +=+ =+=+ + +=+=+=+=+=+= =+=+=解
10、：( )( )( )( )4 124142701010042104010041704070121101241104221104210124 212422124 284= = =+= =+=mmmm.rm.m.mv ovm.m.mv ovffKQffffQAAQffffQAA故得令得解：令( )( )( )( )( ) ( ) ( ) ( ) ( ) 110310104595211083008102001028602183008250 10200250102379522 58854t a n2t a n431100316116570316 107102316104107102105228 113
11、151312312105228 1045250250522810286041102004110237237104100107102 11250205250205943326662262621222206070666022632162626222166001 34 521 32 31 +=+=+=+=+= = = =+=+=.yyggggSSp gpggQQKMH.Qff.LgQAAg yppASgpgpggSLQg.NNp.NNpr ef eLo ei esi epLoor ef eLZL.Lv op of ev oi eo epp解：( ) ( )( ) ( )( ) ( ) ( )( )
12、( ) ( )( ) ( ) ( )( ) ( )( )( ) ( )( ) ( )722169826680423822502566804247947961044 445478212 225904454610442261044122256519744541221224382250257821344541015801041071014322278211580 2438303015801503008203010037010370104107101432100 111104444447070707041707041704147044436260070222122222156600-.AAAAf fA
13、Ak Hz.ffk Hz.ffk HzffAAk HzfLgf.g yppAmS.gpgpRggmS.LQgv ov ov ov o.v ov ov ov o.f ev oi eo epp=+=+=+=解：( )( ) ( ) ( )不能满足解：9.1K522106250110511432 12 1625011830500114r 0 . 11 22620221=+=为奇数为偶数当当解：nnngVtt dntgVIgVtt dgVIgVtt dgVItnIitttgVimmnmmmmnnm0 112c osc os121c os11c os21c os0c os00c osc os135221
14、00( )( ) ( ),3,2,1ktc os2k12k1gV4gV2i0c os00c osc osi0c os00c osc osiii15501k 21kmmD2D1D2D1=+=+= tttgVtttgVi mm当当当当解：( )( ) ( )( ),3,2,1k142c oss i n2142c os2s i n12is i ns i n10s i ns i n100s i ns i n11651 201 200000000= +=+=+=+ + + + += =+=+=+=k59.029 0 0 02 KRR0 . 9co sK0 . 51 5 0 06 0 0 0 1 0 01
15、 4.33RR3F2 0CF2 6.02 0 0 03 0 01 4.32 1r1CF0 1.0CCF0 1 8 7.03 0 0 01 4.329 0 0 03.0 3.01Rm m-1C3.0m3193RRmk326 265.1rR rRRR5 k.1R6 kRR1 0151Rk1 05RRR2 09di dd33 dei 2m i ne212m a xa2aaai 22i 221122121( )1 5 3.04 7 0 021 08 4.51 0 03.08 4.55.2 31 0 05.2 32 04 6 528 4.51 0 0 1 02 0 01 04 6 51 4.322 19
16、622240347.0012300= =i dPo ePLLPgGgpGQQpffQSQCG 解：( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )( ) ( ) ( ) 时，有失真。只产生相移；当时，当有失真。时，当只影响输出幅度。无失真，时，当解：10100101LS01010100111110101LS1001L01LS1001010101010011111tc osVVkmR41vtc ostc osVkmV41tc ost Vc oskmV21itc osm V21v2tc ostc osVVkmR21vtc osc osVVkmR21tc ostc osVVkmR41vtc ostc ostc ostc osVkmV41tc ost Vt c osc oskmVitt c osc osm Vv1249=+=+=+=+=+=+=+=
