1、 6.1 编写一个程序。请用户输入日，月和年。程序返回一年中到给定的日子（包括这一天）的总天数。#include #include #include #include #define SIZE 20#define EASY 3#define YUE 12struct MONTH char month_nameSIZE; /月份名char month_easyEASY + 1; /月份简称int days; /月份的天数;struct MyDATE int year;int month;int day;int leap_year(int year);int GetMonth(char month
2、);void GetDate(struct MyDATE *date);struct MONTH yearYUE = “january“,“jan“,31,“february“,“feb“,28,“march“,“mar“,31,“april“,“apr“,30,“may“,“may“,31,“june“,“jun“,30,“july“,“jul“,31,“august“,“aug“,31,“september“,“sep“,30,“october“,“oct“,31,“november“,“nov“,30,“december“,“dec“,31;int main() int mnth,day
3、s,alldays,nowdays;MyDATE mydate;GetDate(days = (mydate.month = mydate.month; -mnth)days += yearmnth - 1.days;/printf(“%d 天n“,days); /到年后的天数days = days - mydate.day + 1;/ printf(“%d 天“,(alldays-days);/days = days - mydate.day + 1;nowdays=alldays-days;/ printf(“%d 年%d 月%d 日到年底还有%d 天。n“,mydate.year,myd
4、ate.month,mydate.day,days);printf(“到%d 年%d 月%d 日还有%d 天。n“,mydate.year,mydate.month,mydate.day, nowdays);fflush(stdin);system(“pause“);return 0;void GetDate(struct MyDATE *date) int flag,days,addday;char mnth15;printf(“请输入日期(空格隔开 ) : “);do scanf(“%d%s%d“,flag = 0;if(date-year year 99999999) flag = 1;
5、printf(“你的输入有误(年份应在 1 - 99999999 之间)n“);printf(“请重新输入日期(空格隔开 ) : “);continue;if(mnth0 = 0 else date-month = GetMonth(mnth);if(date-month month YUE) flag = 1;printf(“你的输入有误(月份应在 1 - 12 之间, 或英文的全写，或缩写 )n“);printf(“请重新输入日期(空格隔开 ) : “);continue;addday = (date-month = 2) ? leap_year(date-year) : 0;days =
6、 yeardate-month - 1.days + leap_year(date-year) + addday;if(date-day day days) flag = 1;printf(“你的输入有误(%d 月的日期应在 1 - %d 之间)n“,date-month,days);printf(“请重新输入日期(空格隔开 ) : “);continue;while(flag);int leap_year(int year) return year % 4 = 0 /判断是不是闰年int GetMonth(char mnth) int i,CmpRes1,CmpRes2;for( i = 0
7、 ; i #define CSIZE 4void eatline(void);void get_score(struct student *);float get_avr(struct student *);struct namechar firstname5;char lastname10;struct studentstruct name sname;float grade3;float average;int main(void)struct student njust981021CSIZE;int i;for(i=0;isname.lastname);scanf(“%f%f%f“,s-
8、grade0=a;s-grade1=b;s-grade2=c;float get_avr(struct student *s) return (s-grade0+s-grade1+s-grade2)/3.0;6.3 设计一个函数，把输入的十进制整数转化为八进制数。要求用递归和循环两种方法#include int fun(int x); /定义函数void maina();void main(void)maina(); int fun(int x) if(x8) return x;return x%8+10*fun(x/8);void maina()int x;printf(“请输入一个十进制的数：n“);scanf(“%d“,printf(“十进制:%dn“,x);x=fun(x);printf(“八进制:%dn“,x);
