1、 磁性转变对热力学性质的影响 1 热容的非磁性部分，并画出草图Gmno-mag = -5179+117.85 T 22.1 T ln(T) 0.0048 T2S=- (117.85-22.1( ln (T)+1)-0.0096T)H=G+TS = -5179+117.85 T 22.1 T ln(T) 0.0048 T2 - (117.85-22.1( ln (T)+1)-0.0096T)TH =Cp n0-magdTCpno-mag = 22.1 +0.0096*T2030405060708090426283032Cpno-mag (J/ol)Temprature (K)2 热容的磁性部分，
2、并画出草图Cpmag = R*c()*ln(1+Bo)C() = (474/479)(1/p-1)(23+2/39+2/515)/D 1C() = 2-5+2/3-15+2/5-25/D 1p=0.28 =T/T* T*=633 K Bo=0.52 R=8.31451D=(518/1125)+(11692/15975)(1/p-1)=2.342457Cpmag = 8.31451*(ln(1.52)*(474/479)(1/0.28)-1)(23+2/39+2/515)/ 2.342457 =T/633 T633Cpmag = 8.31451*(ln(1.52)* 2-5+2/3-15+2/5
3、-25/ 2.342457 =T/633 T63325030350404500506065070750808509024681012 Cpmag (J/ol) Temprature (K)3 热容的非磁性部分和磁性部分之和, 并画出草图Cp = Cpmag + Cpn0-mag Cp = 22.1 +0.0096*T + 8.31451*(ln(1.52)*(474/479)(1/0.28)-1)(23+2/39+2/515)/ 2.342457 =T/633 T633Cp = 22.1 +0.0096*T + 8.31451*(ln(1.52)* 2-5+2/3-15+2/5-25/ 2.3
4、42457 =T/633 T6332503035040450050606507075080850904262830323436384042 Cp (J/mol)Temprature (K)T=63公式22.1 +0.0096*T8.31451*(ln(1.52)*(474/479)*(1/0.28)-1)*(2*(x/633)3)+(2/3)*(x/633)9)+(2/5)*(x/633)15)/2.3424578.31451*(ln(1.52)* 2*(x/633)(-5)+(2/3)*(x/633)(-15)+(2/5)*(x/633)(-25)/ 2.342457(x-632.8)*30
