1、 9 32 ()K0+000K2+212.567 I 32 http:/ XXK0+000K2+212.5672212.56760km/h,10m1-23-45-6-7- II 32 http:/ Abstract The design is very important to us. Not only because this is our last assignment beforegraduation, but also it can enhance our ability.In this design, our task is to design an secondary road.
2、The road, which is 2212.567 m fromK0+000 to K2+212.567. The design speed is 60km/h and the wide of the subgrade is 10m.Our prime contents of the design project includes:(1) Make sure the vertical section in condition on the landform which is known.(2) The design of the subgrade, and the work involve
3、s a lot of items: analyze the stability ofbrae; the fill or dig height of every peg and so on.(3) The design of pavement, and this contents that the select of the construction about concreteand asphalt pavement in different case.(4) The design of the drainage project, protective project, subgrade re
4、inforced project, and theseare very important to the whole work.(5) The design of the bridge and culverts which include size and form.(6) Translate an English article into Chinese.(7) Investigate the monograph which about a new technique or a new viewpoint in this field.Keywordsway roadbed road surf
5、ace bridge culvert I 32 1 . 1 1.1 - 1 1.2 1 1.3 1 1.4 2 1.4.1 . 2 1.4.2 . 4 1.5 4 1.5.1 . 4 1.6 5 1.6.1 . 6 1.6.2 . 6 1.6.3 . 6 2 . 7 2.1 7 2.1.1 . 7 2.1.2 . 7 2.1.3 . 7 2.2 8 2.3 9 2.4 9 2.5 11 2.5.1. . 11 2.5.2 . 11 2.5.3 . 12 2.5.4 . 13 2.5.5 . 14 2.6 15 2.6.1 . 15 2.6.2 . 16 2.6.3 . 16 3 . 20 3.
6、1 20 II 32 3.2 20 3.3 20 3.3.1 . 20 3.3.2 . 20 3.3.3 . 21 3.4 21 3.4.1 . 21 3.5 - 22 3.5.1 - . 22 3.5.2 - . 22 3.5.3 - . . 23 24 1 32 1 1.1 - (1) -(2) (3)6 s60km/h200m125m776 s722 1.2 SC 1.3 2 32 12 1.4 1 8(m)752(m)10 9(m)20003(km/h)60 10(m)15004(m)125 11(m)1505(m)200 12 1/300;6(m)15001/1007()6 13 -
7、 1-11-1 1.4.1 JD1 3 32 1-2 JD1:R=255mmRVLs65.2925560035.0035.033=mVLs5036.36036.3)(min=mLs105= 492400R255mml1050= mqpRT54.1702tan)(=+?+= mlRL859.3242180)2(00=+?= mRpRE678.272sec)(=?+= 221.162=?=LTJ 5.5220=lq801.12420=Rlpo796.119000=Rl JD1K0+563.2 ZH=JD1-170.54=K0+392.66 HY=ZH+105=K0+497.66 QZ=ZH+324
8、.859/2=K0+555.089 YH=HZ-105=K0+612.519 HZ=ZH+324.859=K0+717.519 ZHTpqHYLsoBoaBoQZLRYHEJDaHZ 5 32 RL= LR= 1-11T 22RLT= 1-12h Rxh22= 1-13E=ERT22 82RE=48TL= 1-141K0+370474mi1=-4.973%i2=2.432%,= i2-i1=2.432%-4.973%=7.405%R=1800mRL=18007.405%=133.29m22RLT=66.645m82RE=8L=1.234m2=K0+370-T=K0+303.351=474+T7
9、.405%=478.935m23 1.6 - 6 32 1-234 1.6.1 23.5m20.75m20.75m7+1.5+1.5=10m2%4-1 4-1 1.6.2 11. 511.7510.510.75 1.6.3 7 32 2 2.1 2.1.1 111.511.75210.510.753 2.1.2 2.1.3 1 8 32 cmCBR%cm 0306 10 30804 10 801503 15 1502. 150306 1024%3cm% 030 953080 9580150 94 15092030 95 2.2 - 9 32 -3m0.5m 2.3 133233 2.4 12 10 32 3K0+960K1+100140m24m41010cm2m30cm10m20mm15cm54%75% 11 32 3%1.0m0.2m15- 2.5 2.5.1. -
