1、-College Major and classNo.Name SealeduplineUniversity Physics Test paper of CSU (20102010)No One two three four five six totalScore Reader Re-checkerOne: Select the right answer in the brackets( in each problem):41. A solid non-conducting sphere of radius R has a non-uniform charge distribution of
2、volume density , where is a constant and is the distance from the center of the srR=srrsphere. So the total charge on the sphere is (A) ; (B) (C) ; (D) . 34spr3sr2spr34sRpr2. The wire shown in figure carries current I. So the magnetic field B is produced at the center C of the semicircle by the tota
3、l wire is (A) 0; (B) ;RI2/0(C) ; (D) .0/4IRm3.Two concentric thin metal shells, radii are and respectively. If the two shells12charged and and their potentials are and respectively. Now if we 1q2Uconnect the two shells with conducting wire, their potential is: (A) (B) (C) (D) 1U212+12()+4.As shown i
4、n figure ,uniform magnetic field is confined in long cylindrical space .If ,so the magnitude of the induced electric field 0dBtof point p outside the cylinder is:E(A) (B) (C) 2Rrdt02rdBt二、选择题(本题 10分，每小题 2分)三、四、ScoreReadertitle 1 2 3 4 5 6 7 8 9 10answersBRrpRCLLI I5. The Maxwell equation which descr
5、ibes the variable electric field will produce magnetic field is (A) (B) (C) (D)6As shown in right figure , the magnetic field is placed in the direction of negative direction of y-axis ,if we know that the electric potential difference between a and b , so the material is 0aU(A) N type (B) P type(C)
6、 metal (D) not certain.7. Which of the following descriptions of wave function is right? (A) is the probability of finding the particle at position r;(B) is probability density of finding the particle at position r at time t;(C) is probability density of finding the particles at position r at time t
7、;(D) is probability of finding the particles at position r at time t.8. If the quantum number n=1, which of the following quantum state is possible：(A) (1,1,0,1/2) (B) (1,1,0,0) (C) ( 1,0,0,-1/2) (D) (1,0,0,0)Two ( in each problem): Write the right answer in blanks41. The maximum kinetic energy of a
8、n electron ejected from a sodium surface whose work function is 2.28 when illuminated by light of wavelength 410 is eVnmeV2. A circular coil of wire has a diameter of 5.0 cm and contains 25 loops, so the magnetic moment of the coil when it carries a current of 1.5 A is . 2A3. If an electron that has
9、 velocity moves through the magnetic 66(2.01)(3.0)vij=+field , so the force on the electron is . (0.3).15Bij=-4. According to Borns statistical interpretation to wave function, the standard conditions of wave function are: (1)_ ;(2) _ ;(3) _ . 5. A wire is formed into the shape of two half circles c
10、onnected by equal-length straightsections as shown in figure .A current i flows in the circuit anticlockwise as shown ,the magnetic field at the center C is .6. Two long parallel wires, both of radius a and whose centers are a distance d apart, carry current in opposite directions. Show that ,neglec
11、ting the flux(磁通) within the wires ,the inductance (电感)of unit length of a pair of wires is .7. The ground-state energy of electron is -13.6eV,so the energy of the second excited states is .Scorereader),(tr2),(tSVDdr=ALSBEdlt=-A0Sd=ALSDHdlJdt=+1R2I C 2azbIxByThree( ): The plastic rod shown in figure
12、 has length L and a non-uniform linear charge density 9,where c is a positive constant .With V=0 at infinity, find the electric Potentialxl=(a)at point on the x axis, a distance d from one end and 1p(b) point on the y axis ,a distance y from one end of the rod.2Four( ):As shown in right figure ,an i
13、nfinite length thin metal plate carries a current I which 9uniformly distributes in the plate , please work out the magnetic field produced by the current at point P. ScorereaderScorereaderP1 oxyd LyP2PadIFive ( ):Figure shows a rectangular loop of wire immersed in a non-uniform and 1varying magneti
14、c field that is perpendicular to and directed into the page. The field magnitude is given by , with B in Teslas, t in seconds and x in meters. The 240Btx=loop has width and height .What are the magnitude and direction of .3Lm.hmthe induced emf(感生电动势) around the loop at ?10ts=Six ( ): The wave functi
15、on of particles in one dimensional potential well with 1width a is , )sin()xAxapy=0please work out the following problems:(1) Normalization constant A;(2) Where is the maximum probability of finding the particles when n=3?Scorereaderscorereaderxy BLhAppendix: answers for 0813-0815One: Select the rig
16、ht answer in the brackets ( in each problem)41 B 2 C 3 B 4 A 5 D 6 A 7 C 8 C Two ( in each blank): Write the right answer in blanks41 2 3 4 (a) single-value; (b) continuous;0.75eV20.6m14(.0)Nk-(c) finite 5 6 7 12()4IR-lndaLmp=1.5eV-Three ( ):9Solution: We select point o as the origin and select the
17、element charge at the dqxl=distance to the origin, so according to the definition of electric potential x 2(a): The electric potential at point is 1p1000(ln)4()4()4LLdqcxdcdLUxpeepe+=-+3(b): The electric potential at point is 2p22 200 0()444LLdqcxdcULyryepe=+-+4Four ( ):9Solution: We select the left
18、 side of the plate as the origin and select the element current ( )at the distance to the origin ,according the magnetic field of the Idixa=2xinfinite long straight wire carrying current:0()diBaxmp+-3So: 00ln22IIdd=-2Direction: perpendicular the paper inward. Five ( ):1Solution: Because the magnitud
19、e of the magnetic field is changing with the time , the Bmagnetic flux through the loop is also changing .so we can take the differential Bfarea ( )with its normal being parallel to , and the flux through dAhx=2the loop is 240BdABhdxtxdf = take this integration and inserting the integration limits a
20、nd get:=.3m, when ,according to 0.32224.7Bthxdtf=0.2hFarady law at any time :1.4Btdtfe2For , 0s=.VDirection: counterclockwise around the loop at this time. 1Six ( )1Solution: (1) according to the normalization condition:22200()sin1aa axdAxdApy= 2So: a(2) The probability density of finding the particles is:, the position of finding the maximum probability satisfies:22()sinxxpy=,2()()00ddxattyWe get: sinp=2Therefore: 23(0,12)xka, 6=We can get the position of maximum probability of finding the particles is:5,26ax 3
