1、Process Design and Analysis,Chapter Eleven,Copyright 2014 by The McGraw-Hill Companies, Inc. All rights reserved.,McGraw-Hill/Irwin,Learning Objectives,LO111: Exemplify a typical business process and how it can be analyzed. LO112: Compare different types of processes. LO113: Explain how jobs are des
2、igned. LO114: Analyze manufacturing, service, and logistics processes to ensure the competitiveness of a firm.,11-2,Process Analysis,Process: any part of an organization that takes inputs and transforms them into outputs Cycle time: the average successive time between completions of successive units
3、 Utilization: the ratio of the time that a resource is actually activated relative to the time that it is available for use,11-3,Analyzing a Las Vegas Slot Machine,Analyzing the mechanical slot machine Analyzing the new electronic slot machine Comparison The slot machine is one of many casino proces
4、ses,11-4,Process Flowcharting,Process flowcharting: the use of a diagram to present the major elements of a process The basic elements can include tasks or operations, flows of materials or customers, decision points, and storage areas or queues. It is an ideal methodology by which to begin analyzin
5、g a process.,11-5,Flowchart Symbols,11-6,Process Flowchart Example (Slot Machine),11-7,Types of Processes,11-8,Buffering, Blocking, and Starving,Buffer: a storage area between stages where the output of a stage is placed prior to being used in a downstream stage Blocking: occurs when the activities
6、in a stage must stop because there is no place to deposit the item Starving: occurs when the activities in a stage must stop because there is no work Bottleneck: stage that limits the capacity of the process,11-9,Multistage Process with Buffer,11-10,Other Types of Processes,Serial flow process: a si
7、ngle path for all stages of production Parallel process: some of production has alternative paths where two or more machines are used to increase capacity Logistics processes: the movement of things such as materials, people, or finished goods,11-11,Make-to-Stock versus Make-to-Order,Make-to-order O
8、nly activated in response to an actual order. Both work-in-process and finished goods inventory kept to a minimum. Make-to-stock Process activated to meet expected or forecast demand. Customer orders are served from target stocking level. Hybrid Combines the features of both make-to-order and make-t
9、o-stock.,11-12,Measuring Process Performance,11-13,Production Process Mapping and Littles Law,Total average value of inventory Sum of the value of raw materials, work-in-process, and finished goods inventory Inventory turns Cost of goods sold divided by the average inventory value Days-of-supply Inv
10、erse of inventory turns scaled to days Littles law There is a long-term relationship among inventory, throughput, and flow time Inventory = Throughput rate x Flow time,11-14,Example 11.1: Car Batteries,Average cost $45 12 hours to make a car Assembles 200 cars per 8-hour shift Currently one shift Ho
11、lds on average 8,000 batteries in raw material inventory,11-15,Example 11.1: Average Inventory,WIP = Throughput x Flow time WIP = 25 batteries x 12 hours WIP = 300 batteries Total = 8,000 + 300 = 8,300 batteries,11-16,Example 11.1: Value and Flow Time,Value = 8,300 x $45 = $375,000 Flow time = Inven
12、tory/Throughput Flow time = 8,000/200 = 40 days,11-17,Behavioral Considerations in Job Design,Specialization of labor Made high-speed, low-cost production possible Greatly enhanced standard of living Adverse effects on workers Job enrichment Making job more interesting to the worker Horizontal enric
13、hment: worker performs a greater number of variety of tasks Vertical enrichment: worker is involved in planning, organizing, and inspecting work,11-18,Work Measurement and Standards,Work measurement is a process of analyzing jobs for the purpose of setting time standards. Why use it? Schedule work a
14、nd allocate capacity Motivate and measure work performance Evaluate performance Provide benchmarks,11-19,Work Measurement Techniques,Direct methods Time study Work sampling Indirect methods Predetermined motion-time data system Elemental data,11-20,Example 11.2: Bread Making,Current Layout,11-21,Exa
15、mple 11.2: Running at 100 Loaves per Hour,Both bread making and packaging operate the same amount of time. Capacity is 100 loaves per hour. Packaging is idle for a quarter hour. Has 75 percent utilization.,11-22,Example 11.2: Bread Making on Two Parallel Lines,11-23,Example 11.2: Multiple Shifts,Bre
16、ad making runs two shifts. Produces 200 x 8 x 2 = 3,200 Packaging runs three shifts. Produces 133.3 x 8 x 3 = 3,200 Capacities are roughly equal.,11-24,Example 11.3: A Restaurant,11-25,Consider the restaurant in the casino. Because it is important that customers be served quickly, the managers have
17、set up a buffet arrangement where customers serve themselves. The buffet is continually replenished to keep items fresh. To further speed service Fixed amount is charged for the meal. Customers take an average of 30 minutes to get their food and eat. They typically eat in groups (or customer parties
18、) of two or three to a table. The restaurant has 40 tables. Each table can accommodate four people. What is the maximum capacity of this restaurant?,Example 11.3: Solution Approach,11-26,Utilization: It is easy to see that the restaurant can accommodate 160 people seated at tables at a time. Actuall
19、y, in this situation, it might be more convenient to measure the capacity in terms of customer parties because this is how the capacity will be used. If the average customer party is 2.5 individuals, then the average seat utilization is 62.5 percent (2.5 seats/party 4; 4 seats/table) when the restau
20、rant is operating at capacity. Cycle time: When operating at capacity, is 0.75 minute (30 minutes/table: 40 tables). So, on average, a table would become available every 0.75 minute or 45 seconds. Capacity: The restaurant could handle 80 customer parties per hour (60 minutes/0.75 minute/party).,Exam
21、ple 11.3: Challenges in Restaurant Problem,11-27,The problem with this restaurant is that everyone wants to eat at the same time. Management has collected data and expects the following profile for customer parties arriving during lunch, which runs from 11:30 a.m. until 1:30 p.m. Customers are seate
22、d only until 1:00 p.m.,Example 11.3: Arrival Data,11-28,Example 11.3: Restaurant,11-29,Restaurant operates for two hours for lunch and the capacity is 80 customerparties per hour. A simple way to analyze the situation is to calculate how we expect the system to look in terms of number of customers b
23、eing served and number waiting in line at the end of each 15-minute interval (a snapshot every 15 minutes). The key to understanding the analysis is to look at the cumulative numbers. The difference between cumulative arrivals and cumulative departures gives the number of customer parties in the res
24、taurant (those seated at tables and those waiting). Because there are only 40 tables, when the cumulative difference through a time interval is greater than 40, a waiting line forms. Cycle time for the entire restaurant is 45 seconds per customer party at this time (this means that on average, a tab
25、le empties every 45 seconds or 20 tables empty during each 15-minute interval). The last party will need to wait for all of the earlier parties to get a table, so the expected waiting time is the number of parties in line multiplied by the cycle time.,Example 11.3: continued,11-30,In the following t
26、able, when the cumulative number of parties is 50, there are 10 parties waiting to be seated (since there are only 40 tables). The average time they wait is 10 x 45 secs = 7.5 minutes. During 12:00 to 12:15, parties that arrived during 11:30 to 11:45 would have left, which makes the cumulative numbe
27、r of parties at the end of 12:15 = 50 (number at the end of 12:00) + 30 (arrivals during 12:00 to 12:15) 15 (departures during 12:00 to 12:15) = 65.,Example 11.3: Customer Status,11-31,Example 11.3 Customers vs. Time,11-32,Example 11.4: The Balabus (“Tourist Bus”) in Paris,Two hours for the route du
28、ring peak traffic Route has 60 stops Each bus has seating capacity of 50 Another 30 passengers can stand Busy much of the day,11-33,Example 11.4: Initial Analysis,With one bus, maximum wait is two hours. If bus is halfway through cycle, wait is one hour. Average wait is one hour. In general, average
29、 wait is cycle time. If two buses used Cycle time is one hour Average wait is 30 minutes. For a two-minute wait Need four-minute cycle time. Need 30 buses (120 minutes/4 minute cycle time).,11-34,Example 11.4: Capacity,Each bus has total capacity of 80 passengers. 50 seated 30 standing 30 buses can
30、accommodate 1,500 seated 2,400 total,11-35,Example 11.4: Detailed Analysis,11-36,Example 11.4: Conclusion,With 30 buses, many will stand. During morning and afternoon rush, not all customers can be accommodated. Need at least 40 buses during rush hours. With 40 buses all the time 24,000 seat-hours available. 40 buses x 12 hours x 50 seats per bus 25,875 seat-hours needed. 107.8 percent utilization 7.8 percent of customers must stand,11-37,Process Flow Time Reductions,Perform activities in parallel. Change the sequence of activities. Reduce interruptions.,11-38,
