1、二次曲线一个猜想结论的推广5xV?i?cos/(sin)kbao?o?=x+,1sin,cosMFbkaco?o?=+2sincosMFbkaco?o?=x+.xV12tan,tansinsinbbcco?o?o?o?=,xV12o?o?=,M?s?i?(E?12FMF?3?.?M?(12FMFx0.?T?N312,FF?6?q?(?D?;?S?,12,AA?6?D?;?,?q?(?k?c?12,AA?i?,?12,FF?i?,?(?m?6B95C,?CB95C?N?12,AA?(?k.?,?12,FF?i?1,F2F?I?T?N2,?,12,FMF0-?12,FMF0-?,xV12212FF
2、FFa0-0-=,xVOCOBa=,xVB95C?N?12,AA?(?k.?T?N4PA95PB?q?(?D?i?,?i?A95B,?C1PF?(1AFBx0.?,1F?PA?1F0-,?I?T?N2,?1F0-,A,2F?,2F?PB?2F,?I?T?N2,?1F,B,2F?.x“11,PFPF0-=22PFPF=,?1122FaFF=2F,xVE?12PFFx?E?12PFF,xV11PFAPFBx0=x0,?x“E?1PAFx?E?1PAF,xV11PFAAFPx0=x0,xV11AFPPFBx0=x0,?11PFAFBx0?(.?o?r1?a?,?.?;?)?T?N.?q?n?k.20
3、05.10.?:?;?4?d?q?1?:?b?4?:?00(,)Pxy?=?N?:?o?2:Ax+2Cy0DxEyF+=?k,?P?D?(?m?o?,SM?,TN,?C?MN?,ST?.?2?k?4?,?:04?MN?,ST?3?0?0P.?k?:?PMPNkk+=0,?C0MNSTkk+=,?p?(?9?p?.?(?P?=?N?:?o?2:Ax+2Cy0DxEyF+=(*)?k,?P?(?m?o?S95M?T95N.(1)?PM?,PN?6?MN?,ST?;(2)?PM?,PN?6?MN?,ST?.?,?P?i?0,(),oxyPMPN?(?m?,kk,?CPM,PN?b?(?m?:00()
4、,yykxxx+=x+00().yykxxx+=x+?MN,ST?b?(?m?,0,0.mxnypqxrys+=+=?I?2?q?t?(,?9?,SMNT?:?b?:00()yykxxx+x+x+00()yykxxx+x+x+()()0.mxnypqxryso?+=?(,?:22()(1)kkmqxnryo?o?+x+()kkmrnqxyo?o?+x+x+x+000(2)kkxkykymspqxo?o?x+x+x+x+20000(2)kxkxynsprykkxo?o?+x+x+2000()0.kkxyypso?x+=?,(*)?a?,?Ox1FCBMy1A2A1F2F2FAEPOyx2F1F1
5、F2F2:6,1,()0.kkmqAnrCkkmrnqo?o?o?+=y?y?+=y?y?+x+=y?ID?:1Cnro?x+=,(1)?(D?D?,?:(1)0mrnqkkCnr+x+x+=.(1)()mqkkCnr+=x+,(1)()()mqkkCnr+=x+x+x+,?,MNSTmqkknr=x+=x+.xV(1)()PMPNMNSTkkCkk+=x+.?PMPNkk+?,?CMNSTkk+?;?,?MNSTkk+?,?CPMPNkk+?.?PM?,PN?6?MN?,ST?.?m?9,?0PMPNkk+=?,?I?9?k?4?.(2)?(D?D?,?:(1)mqkkCAnr+x+=.(1
6、)()()mqkkACnr=+x+x+x+?(1)PMPNMNSTkkACkk=+x+?PMPNkk?,?CMNSTkk?;?,?MNSTkk?,?CPMPNkk?.?,?PM?,PN?6?MN?,ST?.?m?9,?1kk=x+?,11MNSTAkkC+=x+,?F?9?b?A?.?:?o?22:AxCyDx+Ey+0F+=?3?P?(?m?T?,SM?,TN,?C11MNSTAkkC+=x+.?o?r1?.?04?(?E?0P?2?i,?.?;?4?,.?.2002.9.?n?F?N?q?q?N?q?6?F?q?q?,?6?.?,?6?.?,?6?04?95?0P?.?F?,?(?F?1?9?;?,?(?F?,?P?(?95?.?F?6?;?)?N?,?N?,?I?,?M?x?.?,?=?n?,?a?.?P?k?.?N,?)?,?N?F?.?,?N?F?1?.?b?n?n?F?N?q?q?N.1?F?N?=?1?q?N?1(IMO-22?)?P?E?ABC?,P?9?)?,BCCAAB?:?12,dd3d.?,BCaCAbABc=,?123()2ABCabcabcdddS+
