1、TIME 1 hourINSTRUCTIONS TO CANDIDATESWrite your name, Centre number and candidate number in the spaces at the top of this page.Answer all questions.Write your answers in the spaces provided on the question paper.INFORMATION FOR CANDIDATESThe number of marks is given in brackets at the end of each qu
2、estion or part question.You may lose marks if you do not show your working or if you do not use appropriate units.CAMBRIDGE INTERNATIONAL EXAMINATIONSGeneral Certificate of Education Advanced Subsidiary Leveland Advanced LevelPHYSICS 9702/2PAPER 2 AS CoreOCTOBER/NOVEMBER SESSION 20021 hourCandidates
3、 answer on the question paper.No additional materials.This question paper consists of 14 printed pages and 2 blank pages.SPA (NF/CG) S21714/3 CIE 2002 Turn overCandidateCentre Number NumberCandidate Name FOR EXAMINERS USE29702/2/O/N/02Dataspeed of light in free space, c = 3.00 108ms1permeability of
4、free space, H92620=4H9266 107Hm1permittivity of free space, H92800= 8.85 1012Fm1elementary charge, e = 1.60 1019Cthe Planck constant, h = 6.63 1034Jsunified atomic mass constant, u = 1.66 1027kgrest mass of electron, me= 9.11 1031kgrest mass of proton, mp= 1.67 1027kgmolar gas constant, R = 8.31 J K
5、1mol1the Avogadro constant, NA= 6.02 1023mol1the Boltzmann constant, k = 1.38 1023JK1gravitational constant, G = 6.67 1011Nm2kg2acceleration of free fall, g = 9.81 m s239702/2/O/N/02Turn overFormulaeuniformly accelerated motion, s = ut + onenumeratorcenteredtwodenominatorcentered at2v2= u2+2aswork d
6、one on/by a gas, W = pH9004Vgravitational potential, =simple harmonic motion, a = afii98532xvelocity of particle in s.h.m., v = v0cos afii9853tv =afii9853(x20 x2)resistors in series, R = R1+ R2+ . . .resistors in parallel, 1/R =1/R1+1/R2+ . . .electric potential, V =capacitors in series, 1/C =1/C1+1
7、/C2+ . . .capacitors in parallel, C = C1+ C2+ . . .energy of charged capacitor, W =onenumeratorcenteredtwodenominatorcenteredQValternating current/voltage, x = x0sin afii9853thydrostatic pressure, p = qghpressure of an ideal gas,p =onenumeratorcenteredthreedenominatorcentered radioactive decay, x =
8、x0exp( afii9838t)decay constant, afii9838 =critical density of matter in the Universe, q0=equation of continuity, Av = constantBernoulli equation (simplified), p1+onenumeratorcenteredtwodenominatorcenteredqv21= p2+onenumeratorcenteredtwodenominatorcenteredqv22Stokes law, F = ArH9257vReynolds number,
9、 Re=drag force in turbulent flow, F = Br2qv2qvrH92573H028H9266G0.693tonenumeratorcenteredtwodenominatorcenteredNmVQ4H9266H92800rGmr49702/2/O/N/02Answer all the questions in the spaces provided.1 (a) (i) Define density.(ii) State the base units in which density is measured.2(b) The speed v of sound i
10、n a gas is given by the expressionv =,where p is the pressure of the gas of density . is a constant.Given that p has the base units of kg m1s2, show that the constant has no unit.32 A student uses a metre rule to measure the length of an elastic band before and afterstretching it.The lengths are rec
11、orded aslength of band before stretching, L0= 50.0 0.1 cmlength of band after stretching, LS= 51.6 0.1 cm.Determine (a) the change in length (LS L0), quoting your answer with its uncertainty,(LS L0) = cm 1pForExaminersUse59702/2/O/N/02Turn over(b) the fractional change in length, ,fractional change
12、= . 1(c) the uncertainty in your answer in (b).uncertainty = 3(LS L0)L0ForExaminersUse69702/2/O/N/023 A ball falls from rest onto a flat horizontal surface. Fig. 3.1 shows the variation with time t ofthe velocity v of the ball as it approaches and rebounds from the surface.Fig. 3.1Use data from Fig.
13、 3.1 to determine(a) the distance travelled by the ball during the first 0.40 s,distance = . m 2 ForExaminersUse0.2 0.3 0.4t/s0.5 0.6 0.700-1-2-3-4123450.1v/ms179702/2/O/N/02Turn over(b) the change in momentum of the ball, of mass 45 g, during contact of the ball with thesurface,change = N s 4(c) th
14、e average force acting on the ball during contact with the surface.force = . N 24 (a) Explain what is meant by the concept of work.2(b) Using your answer to (a), derive an expression for the increase in gravitational potentialenergy Epwhen an object of mass m is raised vertically through a distance
15、h nearthe Earths surface.The acceleration of free fall near the Earths surface is g. 2ForExaminersUse89702/2/O/N/025 The variation with time t of the displacement x of a point in a transverse wave T1is shown inFig. 5.1.Fig. 5.1(a) By reference to displacement and direction of travel of wave energy,
16、explain what ismeant by a transverse wave.1(b) A second transverse wave T2, of amplitude A has the same waveform as wave T1butlags behind T1by a phase angle of 60. The two waves T1and T2pass through thesame point.(i) On Fig. 5.1, draw the variation with time t of the displacement x of the point in w
17、ave T2. 2(ii) Explain what is meant by the principle of superposition of two waves.2(iii) For the time t = 1.0 s, use Fig. 5.1 to determine, in terms of A,1. the displacement due to wave T1alone,displacement = .2. the displacement due to wave T2alone,displacement = .3. the resultant displacement due
18、 to both waves.displacement = .3234t/sT1560-AA1xForExaminersUse99702/2/O/N/02Turn overBLANK PAGETurn over for question 6109702/2/O/N/026 An electron travelling horizontally in a vacuum enters the region between two horizontalmetal plates, as shown in Fig. 6.1.Fig. 6.1The lower plate is earthed and t
19、he upper plate is at a potential of + 400 V. The separation ofthe plates is 0.80 cm.The electric field between the plates may be assumed to be uniform and outside the platesto be zero.(a) On Fig. 6.1,(i) draw an arrow at P to show the direction of the force on the electron due to theelectric field b
20、etween the plates,(ii) sketch the path of the electron as it passes between the plates and beyond them.3(b) Determine the electric field strength E between the plates.E = V m12electronpathP+ 400Vregion ofelectric fieldForExaminersUse119702/2/O/N/02Turn over(c) Calculate, for the electron between the
21、 plates, the magnitude of(i) the force on the electron,force = N(ii) its acceleration.acceleration = m s24(d) State and explain the effect, if any, of this electric field on the horizontal component ofthe motion of the electron.2ForExaminersUse129702/2/O/N/027 A student set up the circuit shown in F
22、ig. 7.1.Fig. 7.1The resistors are of resistance 15 and 45 . The battery is found to provide 1.6 105J ofelectrical energy when a charge of 1.8 104C passes through the ammeter in a time of1.3 105s.(a) Determine(i) the electromotive force (e.m.f.) of the battery,e.m.f. = V(ii) the average current in th
23、e circuit.current = A4A15 45 ForExaminersUse139702/2/O/N/02Turn over(b) During the time for which the charge is moving, 1.1 105J of energy is dissipated in the45 resistor.(i) Determine the energy dissipated in the 15 resistor during the same time.energy = . J(ii) Suggest why the total energy provide
24、d is greater than that dissipated in the tworesistors.48 A nucleus of an atom of francium (Fr) contains 87 protons and 133 neutrons.(a) Write down the notation for this nuclide.Fr 2(b) The nucleus decays by the emission of an -particle to become a nucleus of astatine (At).Write down a nuclear equati
25、on to represent this decay. 2ForExaminersUse149702/2/O/N/029 An aluminium wire of length 1.8 m and area of cross-section 1.7 106m2has one end fixedto a rigid support. A small weight hangs from the free end, as illustrated in Fig. 9.1.Fig. 9.1The resistance of the wire is 0.030 and the Young modulus
26、of aluminium is 7.1 1010Pa.The load on the wire is increased by 25 N.(a) Calculate(i) the increase in stress,increase = Pa(ii) the change in length of the wire.change = . m4wireweight1.8mForExaminersUse159702/2/O/N/02(b) Assuming that the area of cross-section of the wire does not change when the load isincreased, determine the change in resistance of the wire.change = 3ForExaminersUse169702/2/O/N/02BLANK PAGE
