1、 1 (pF ).(LCH)(.QR则L取 RffQ(k H z )fMH z解: f.15910159101432111591014321010010100101010121010990101211362620603670036700时,产生并联谐振。CL或 CL) 当(时,产生串联谐振。CL或 CL) 当(时,产生并联谐振。CL或 CL) 当解: (22021101220211012202110111311211123RR CLR)LCL(j R)LCL R (j CLRCj RLj R)Cj L )( Rj (R证明:Z 2112111133220020020000 3180104045
2、01053514321121535100160512405354501605151431223202222H.CCL故采用后一个不合理舍去pF-得 CCC由pF得 CCC由解:。L C C mVVQVVmA.RVIHCLRC解: Q-SmC o mL o m-omom-212101212205101112101001051143211212510100105114321153303122602001260002 j.j.CjRZ.QLQLRpFCpF.LCCCC.VVQH.C解: LXXXXXXXSC79674710200101432174717471001025310143210521025
3、31014322001001025310143211100101025310100101432116312606666000626200122620 。21k 0.5R ,R,故0.5QQ, 则f22f因 2320105105552310023100101501052220105010514321173000 . 70 . 7660036700012620电阻所以应并上.ffQffQH.C解: L. gQ Cff CfC f证明: 0700 070 22483 MH z.Qff.LRQk RCCCCRRRk .CLQRMH z.LCfpF.CCCCCCC解: CL.LPiPi481228106
4、41222810801064114321088588552020202092010920102020108010064110318108014321213182020202020205936070663020211021261201260102102 RZ3 0Z20Z1123f1f1f1 解:3 .j.jZMZj.jCLjRZpF.LCk H z.RfQff.RRLQk CRRLZRMZH.RMpF.LCCH.LL解:f.fffP8437680100201018310143210020101771014321101591014322011771015910950143211522810201
5、0222242520201015910143232510159202010159202010183101432218310143220115910159101432111591014321011332662220111266620210222262322022361100706611101112611112662201160116261201216301121 100101410222002010159105010159153367.00111236ffQMRRCRLRfP解:4 013.02001122211222005101001032510102402051010010205101011
6、632207.067101671012671120126722011QffRLQRMkRRLRRMR解:fabf5.75.22303021103001010112118.111020001030014.325.22115.2225.11103001010112111732332001230233200 QQQQffQIICQRQQffQII解: L HL并 联联谐CLL串 联联谐CL解: 125375112183212125102501050501501时,5012.1102501020501501时,20491025010501501时,154266200266200266200TTTffM
7、H zfffMH zfffMH zf当当解:当5 mSj.j.jbajbagrCjbajbaCjggrCjgymSj.jbajbagymSj.j.jbajbaCjgymS.j.j.jbajbaCjgyrCb.grapF.fgCmSrgmS.IgmbbcbcbcbmbbcbceoemfecbcbreebebiebbebebbbTmebebmEeb68.0049.01011.01107.377011031014321733.3327.371011.01107.37187.00187.01011.0110310143241189501011.01102410143210754.01070102410
8、1432110754070112410250143210737273710754050754015026112674223127222222322221272222127322127363300解: 4124142701010042104010041704070121101241104221104210124212422124284mmmm.rm.m.mvovm.m.mvovffKQffffQAAQffffQAA故得令得解:令6 1103101045952110830081020010286021830082501020025010237952258854t a n2t a n43110031
9、6116570316107102316104107102105228113151312312105228104525025052281028604110200411023723710410010710211250205250205943326662262621222206070666022632162626222166001345213231.yyggggSS.pgpgg.QQKMH.Qff.LgQAA.gyppASgpgpggS.LQg.NNp.NNprefeLoeiesiepLoorefeLZL.Lvopofevoieoepp解:7 7221698266804238225025668042
10、479479610444454782122259044546104422610441222565197445412212243822502578213445410158010410710143222782115802438303015801503008203010037010370104107101432100111104444447070707041707041704147044436260070222122222156600-.AAAA.ffAAk H z.ffk H z.ffk H zffAAk H zfLgf.gyppAmS.gpgpRggmS.LQgvovovovo.vovo.vov
11、o.fevoieoepp解: 不能满足解:9.1K522106250110511432121625011830500114r 0 . 1122620221H.CfLpFCpCC oe 74.73.05.2 4.364.265.2144 220refeSvo CyA 解:8 1639106010465222601049101004104652741049210405745131149100101000104652106205745134910010100010465210201004405745131000100441000120513731186073118731181181010001046
12、52111741030706123121206321123320202236123601012222236112563423612231201.KkH.QffgCQ.gyppAS.QCgpgSQCggpF.CpCCpFCCC.LLLLHCL.rZL.Lfevoioio,则。若为临界耦合,即初、次级回路参数相等解: nAk T G iVk T R v-nnnn65121010290103814f46512101000290103814f4:解204732327232 13322121313232132133221132133221133221123222123213322113213322113
13、3221123222124444444444214RRRRRRTRRTRRTRRGGGGTGTGTTfGGGkTfGTGTGTkfGkTfGkTfGkTiiii又RRRRTRTRTTfRRRkTfRTRTRTkfRkTfRkTfRkTvvvvnnnnnnnnnnnnnnnnnn解:9 略同理可证得代入消去由后相加得乘与乘由代入得证明:22yy2yy2yyyyy2y2yy2yyyyy6y412yyyy2yyy62yyy2yyy4553243211184feferiefefeiefeieie2ieic b 2fe1fefeiefeieie2ieb12c b 21fe21fe2oefeieofefe
14、fefefc b 2fe2oefeie1fefefe212222122121121212122212121222111111yyyyyyyyyyyyyyyyyyVyyyyyyVyyyyyyIIVyyVyyyIyyIyyyyyyyyyyyyyyyyVyyyyyyVyyyyIyyyVyVyIyyVyIyyyVyVyIVVyVyyyVyIVyyVyVVyVyVyVyIVyyVyVVyVyVyVyIVyVyIVyVyIreoereoereiereoereoereiereoereoereiereoerebeoereiereoerecoerebeoeierecoefebreoefereoereiereoe
15、oereieoeoereiereoebeoereieoecoereiebefecbrecoefecboecoereiebefecbreccecbreceoereiebefecceoefecboececboecefeceoebefeccereiecbrececbreceiecerebeiebceoebefeccerebeieb10 217331902266202163319221232321032.01020095.0110106.121295.0105001010195.011064.01020010106.12210226.01020070192731038.144224AfqIiffAfq
16、IiVfk T rvnCcnnEennbbn解: QfdffffQfAdffAfn 2211234 00 2000202 证明: dB.AA.A.AKFAFFF.TTF.dBF.dBFpppppcnpnnninnn7628881lg2088811020198131207199511120712906011倍98136倍99513244高高高高中高混高混中高 解: RRR RRRRV RVPPPPAAP PPP PPF ssss ssossoppni noso nin 14 411254 2 2nosi解: sLLss ssospso nin G LrCGGLrCGGGI GIPPAPP PPF
17、 14 41264 2 2nosi解: 2849.15981.3 14981.3 127.1AA 1FA 1FFF849.1512dBA981.36dBACBA274pBpAnCpAnBnAnpBPA倍倍为输出级。为中间级,为输入级,解:8 . 1F1.010 1995.110 110FAA 1FA 1FF1010PP PPFCBA284nAnApBpAnCpAnBnA45nosonisin 为下一级。为输入级,前置放大器,解:不能满足要求。设 得到近似线性特性。可只取其级数的前两项线弯曲部分,故围内变化,不会进入曲号电压在特性的线性范勒级数原则,可认为信很小时,根据泰部分,然后当在抛物线上段
18、接近线性较大时,静态工作点选即当,似当成线性元件来处理,该非线性元件就能近时,当解:m000200022200202002VVc os22c os2121c os2c os85tVVVkiVVtVVtVVVktVVkkvimmmmmm11 BZmBBmBBBZooCCVVVV VVi212160c o s60125 。应为最大值,中的二次谐波振幅达到解:为了使 为奇数为偶数当当解:nnngVttdntgVIgVttdgVIgVttdgVItnIitttgVimmnmmmmnnm0112c osc os121c os11c os21c os0c os00c osc os13522100 ,3,2
19、,1ktc o s 2 k12k1gV4gV2i0c o s00c o sc o si0c o s00c o sc o siii15501k21kmmD2D1D2D1tttgVtttgVi mm当当当当解: ,3,2,1k142c o ss i n2142c o s2s i n12is i ns i n10s i ns i n100s i ns i n11651201200000000 kk ktk tmktk tmgVttmgVittmVittmV时,当;时,解:当 21L221221LD2D1L0 vv4kRvvkvvkRiiRv175 解: 21232132212211032132212
20、21103213221221103213221221103142143208185vvbRvvbvvbvvbbRvvbvvbvvbbRvvbvvbvvbbRvvbvvbvvbbRiiiiRiiRiiRvLLLLLLLL 解:12 31310440330220302000c o s0304021304021003040304020300210330402203002134232116322183c os6c os2c osc osc os61c os21c os1c osc os25.121323c osc osc os22c os123c os2c os4c os3c os2432123500
21、0kTqVIkTqVIggkTqVIkTqVIgtkTqVItkTqVItkTqVItkTqVItVkTqtVkTqtVkTqtVkTqaIetVkTqaIdvditgevkTqaIdvdigVbVbggVbVbgttVbtVbVbtVbbtVbtVbtVbbdvditgvbvbvbbdvdigomSomSmcomSomSmomSomSomSomSomomomomStVkTqomSvvBECmvkTqBESBECmmmmcmmmmmmmmmmvvBECmBEBEBEBECmomBEBEBE解: 03430402404303202010404303202010404303202010404303
22、202010423116168255vvavvavvavvavvavvavvaavvavvavvavvaavvavvavvavvaavvavvavvavvaaiiiiisssssssssssssssssss解:13 dBfQfAQQAAdBgggASggmSIggmSIrIIgipcLpcpcociccpcceocEebicEbbETsEc1.30122 81010046521104 73221140104 73004.055.046.94455.035265.0266.9265.05.0265.0261265.0295227.00m a x20m a x22m a x02解: dBgGGgg
23、AdBgggASggmSIggmSIrIIgicLLoccpcociccpcceocEebicEbbETsEc231961.01.01.001.054.1289.59201.01.0454.14101.0302608.02654.12608.05.0265.0261265.03052222m a x02解: 03430402404303202010404303202010404303202010404303202010432116168325vvavvavvavvavvavvavvaavvavvavvavvaavvavvavvavvaavvavvavvavvaaiiiiisssssssssss
24、ssssssss解:扰。信号,则能产生阻塞干互调干扰;若有强干扰,可能产生生交调干扰;有二次项不存在三次项,不会产时产生镜像干扰。由于就会产生中频干扰;当进行混频。只要满足解:因存在二次项,能 i0nin fffff345 14 ,合理选择中频等。提高前端电路的选择性时产生。、的哨叫声在附近,和波段内的干扰在的情况。所以落于数,不考虑大于为本振和信号的谐波次、,因最终出现哨叫声。差拍检波,产生音频,的非线性效应,与中频通过检波器放大后加到检波器上,进入中频放大器,并被它就能和有用中频一道的通带内,合频率接近于中频放大组合频率,如果这些组还存在一些谐波频率和中频电流外,输出电流中,除需要的扰。这
25、是由于混频器的此现象属于组合频率干解:.3139 6kH z139 4kH z931 kH z929 kH z1kH z139 5kH zf930 kH zf160 5kH z5353qp465 kH zf.2.1355SSi 。谐波较小,可以不考虑大于、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,不会产生互调干扰;,、,则会产生互调干扰:解:若满足3qpM H z5.42710357743ff33q3pM H z4.3921035277432f3f2q3pM H z4.6531035377423f2f3
26、q2pM H z3.61810357742ff22q2pM H z2.58310357742f2f1q2pM H z2.844103527742ff2q1pM H z1.8091035774ff1q1pfqfpf36521212121212121s21 MH zfMH zfMH zffffffMH zffffffMH zfMH zfMH zffffffMH zffffffSssssssSSSSSSS16420302302123032302326.02.04.0232228.0232223137500000000000000 解: 。,故没有互调信号输出、 、已知,则会产生互调干扰。解:若满足
27、M H z20323fff2 M H z.19f 6 M H z.19ffqfpf395 i0s2 1s21 15 occcmccCCcmcmCCcmpCCOCCIIgAVPVPIPVPVRPPWIVP7776.125.042.0174.02452226.57522422%3.8365625.0244601001202020查表得解: W.PPPPWRIP.VVgcCkoccmCCcc714170111412915618101270226600220 查表得解: %.IVPW.IRPmA.iImA.IicCCcmcpcomcocc74090302214102002121141282509028
28、23190909076002210m a x1100m a x 解: 222228622020222022202220RILRLRILRCLRIRCL LRIRVP kmkmkmkmPcm 证:16 16.2219.10225.212%3.7636.1319.1017.319.1036.1319.109592.025.21212136.135566.0249592.0436.02.2705566.0253.02.27025.218.02.22496202001001m a x10m a x0m a xm i nPVRPPWPPPWIVPWIVPAiIAiIVgiVvVVcmpCCcmcmcCC
29、occmocccrcCCcCCcm解: pFfXCXQRQRQXHfXLQRRRXpFfXCQRXPVPVRRCLLLLCLLLCLCCCcmp123957.2105014.3212157.2195.161020011001441011054.0105014.3295.16295.1611100144200200112214.14105014.321214.1410144144222422106622122126112122161111202021解: 。变化不大,于欠压状态,减小一半,放大器工作 ;变化不大,于过压状态,增加一倍,放大器工作解:0P2cm0cmP0P2cm0cm 2P2/RI
30、PIR2 5P.02R/VPV1116 PR %4.5703.01510011 111 11 11262221221211 kQQMQQLLrr rk解:17 nHfXLXQRQRQXpFfXCRRQRXpFfXCQRXQPVVPVRLCLLLPLLCPLLLCCLPCLs a tCECCcmP9.191014.325.1225.125.5105011106610112905.51014.321215.51665010150112416.61014.321216.610661066125.012221368112221822222811120202则设解:18 11111X1111QRXLRC
31、RLRCR111111111QRXCRCRCRCR146L122121L122121L121212121C1212121L12L1222211LC21222L122L1222L1121212121121L12L12222L11212121122L1222L1212121211L1C112111211C222122122122121212112121212222222121212121112222222222212121212112122222222121212112222222212121211L1C122112211XQRQQRQQRXQRQQRQQRXRRXRXXRRXXRRXXXRRQR
32、XRXRXRQRXRXRRRXXRRXXXRRXRXRXRRXRXRbXQRQQRXRRQQQRXRRXRXXXRRXXRRXXRRXXXRRQRXRXRXRQRXRXRRRXXRRXXXRRXRXRXRRXRXRaLLLLLLLLLLCCCCLLCCCCCCCLLLCLLLCCCCCCCCCCCLLCCCLCCCCCCCCCCCC,即匹配时并联电路,并设和串联电路改为和将,即匹配时并联电路,并设和串联电路改为和将证: 流表读数减小。电表读数略增,天线电欠压状态,集电极直流中介回路失谐,工作于读数增加;读数略增,天线电流表状态,集电极直流电表天线接地,工作于欠压;读数为读数减小,天线电流表状态
33、,集电极直流电表天线断开,工作于过压解:3201186 %60106%70103103%7.8531062613101196PPPPPPPPWPPPPACcCAkkCA解:19 c0021111c1113kQ39QQ1QQ19rr%90rrr1Q1rr%50rrr1206kkkkkkc故则若则时,解:当解:256 。减小,工作于欠压状态,解: 0o1o2 6060276 P Li RIVIVR 9339286 解: WPQQPWVIPVigVVAiIAVViVVVVVVVVLAcmcmCcrCCcmoCcmBZBCBBbmBoBBBZbm52.847.9100101147.9201.2286.
34、0202.2298.12486.0436.098.17098.126.055.4255.445.16670c os45.16.0c os2960010m a x1m a x1m a x解:20 WPQQPWVIPVVVAiIAVViVVVVVVVVLAcmcmCCcmoCcmBZBCBBbmBoBBBZbm8.85.910010115.926.2188.026.21249.088.0436.002.27002.226.064.4264.45.114.614.670c os5.16.0c os30600101m a x1m a x解: 馈式振荡电路。可能振荡,属于电容反电路计及容反馈式振荡电路时
35、有可能振荡,属于电电路在电路不可能振荡;、容反馈式振荡电路;电路可能振荡,属于电容反馈式振荡电路;电路可能振荡,属于电感反馈式振荡电路;电路可能振荡,属于电解:be3322CgCLCLfdcbhea57 不可能。;反馈式振荡电路,有可能振荡;属于电容;反馈式振荡电路,有可能振荡,属于电感;反馈式振荡电路,有可能振荡,属于电容解:653ffff4ffff2ffff167302130213021解:77 V.mSLCQRgM H z.CCLfPdd080060327.51010520311121001052010143212112177121270解:21 mm.f.d.dB.QpF.dS.C.SdBrmH.Sd.LpF.dS.CMH z.d.fqqdqqq11010151065711065712168004010250051100518194020010963109632212004025042500425001